How many moles of NBR3 can be made from 2.22 x 102 moles of N2 ? N2 + 3 Br2 → 2 NBr3 + 44.0 kJ mol NB13 (2.22 x 102 mol N2)(- -) = mol NBR3 mol N2 b. 2 С. 3 d. 4 f. 253.719 g. 3.38 x 10° h. 3.26 x 103 i. 44.0 j. 1.33 x 102 а. 1 е. 5 k. 9.77 x 103 I. 4.44 x 102 m. 6.66 x 10² n. 500.0 О. 556 р. 90.0 q. 3.2852 r. 159.81 S. 28.013 t. 1.750 u. 0.8750 V. 13.0 w. 0.46306 X. 1.3892 у. 24.5 Z. 38.5 аа. 2.190 bb.

Fundamentals Of Analytical Chemistry
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Author:Skoog
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Chapter4: Calculations Used In Analytical Chemistry
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Problem 4.13QAP
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How many moles of NB13 can be made from 2.22 x 102 moles of N, ?
N2 + 3 Br2
2 NB13 + 44.0 kJ
mol NBR3
(2.22 x 102 mol N2)-
-) =
mol NB13
mol N2
а. 1
b. 2
С. 3
d. 4
е. 5
f. 253.719
8. 3.38 х 100
h. 3.26 x 103
i. 44.0
j. 1.33 x 10-2
k. 9.77 x 103
I. 4.44 x 102
m. 6.66 x 102
n. 500.0
О. 556
р. 90.0
q. 3.2852
r. 159.81
S. 28.013
t. 1.750
u. 0.8750
V. 13.0
w. 0.46306
X. 1.3892
у. 24.5
Z. 38.5
aа. 2.190
bb.
Transcribed Image Text:How many moles of NB13 can be made from 2.22 x 102 moles of N, ? N2 + 3 Br2 2 NB13 + 44.0 kJ mol NBR3 (2.22 x 102 mol N2)- -) = mol NB13 mol N2 а. 1 b. 2 С. 3 d. 4 е. 5 f. 253.719 8. 3.38 х 100 h. 3.26 x 103 i. 44.0 j. 1.33 x 10-2 k. 9.77 x 103 I. 4.44 x 102 m. 6.66 x 102 n. 500.0 О. 556 р. 90.0 q. 3.2852 r. 159.81 S. 28.013 t. 1.750 u. 0.8750 V. 13.0 w. 0.46306 X. 1.3892 у. 24.5 Z. 38.5 aа. 2.190 bb.
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  1. This reaction is endothermic/exothermic (circle one)
    b) How much heat can be evolved/absorbed (circle one) when 2.22 x 102 mol N2 are consumed?

    (answer = 9.77 x 103 kJ)

  2.  
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