How many moles of NBR3 can be made from 2.22 x 102 moles of N2 ? N2 + 3 Br2 → 2 NBr3 + 44.0 kJ mol NB13 (2.22 x 102 mol N2)(- -) = mol NBR3 mol N2 b. 2 С. 3 d. 4 f. 253.719 g. 3.38 x 10° h. 3.26 x 103 i. 44.0 j. 1.33 x 102 а. 1 е. 5 k. 9.77 x 103 I. 4.44 x 102 m. 6.66 x 10² n. 500.0 О. 556 р. 90.0 q. 3.2852 r. 159.81 S. 28.013 t. 1.750 u. 0.8750 V. 13.0 w. 0.46306 X. 1.3892 у. 24.5 Z. 38.5 аа. 2.190 bb.
How many moles of NBR3 can be made from 2.22 x 102 moles of N2 ? N2 + 3 Br2 → 2 NBr3 + 44.0 kJ mol NB13 (2.22 x 102 mol N2)(- -) = mol NBR3 mol N2 b. 2 С. 3 d. 4 f. 253.719 g. 3.38 x 10° h. 3.26 x 103 i. 44.0 j. 1.33 x 102 а. 1 е. 5 k. 9.77 x 103 I. 4.44 x 102 m. 6.66 x 10² n. 500.0 О. 556 р. 90.0 q. 3.2852 r. 159.81 S. 28.013 t. 1.750 u. 0.8750 V. 13.0 w. 0.46306 X. 1.3892 у. 24.5 Z. 38.5 аа. 2.190 bb.
Chapter4: Calculations Used In Analytical Chemistry
Section: Chapter Questions
Problem 4.13QAP
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This reaction is endothermic/exothermic (circle one)
b) How much heat can be evolved/absorbed (circle one) when 2.22 x 102 mol N2 are consumed?(answer = 9.77 x 103 kJ)
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