need help show work in excel please How many work cycles should be timed to estimate the average cycle time to within 2 percent of the sample mean with a confidenceof 98.0 percent if a pilot study yielded these times (minutes): 4.0, 4.5, 5.0, 4.5, 4.5, and 4.0? The standard deviation is 0.376 minutesper cycle. (Use the "mean time" value to 2 decimal places and other values to 3 decimal places for intermediate calculations.Round up your final answer to the next whole number.)Number of work cycles

Given, Percentage of estimated sample mean to be taken p = 2% Confidence interval = 98% z at 98%…

Answered: How many work cycles should be timed to…

Practical Management Science

6th Edition

ISBN:9781337406659

Author:WINSTON, Wayne L.

Publisher:WINSTON, Wayne L.

Chapter2: Introduction To Spreadsheet Modeling

Section: Chapter Questions

Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...

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A Methods and Measurements Analyst needs to develop a time standard for a certain task. The task involves use of a ruler, square, and portable electric saw to mark and cut the "notch" in a rafter (a standard carpentry task of home construction). In a preliminary study, he observed one of his workers performing this task five times. The observations were made in an air-conditioned, well-lit training facility, at ground level, with all tools and equipment clean and readily available. Observation: 1 2 3 4 5 Task time (seconds): 82 74 80 88 76 (a) What is the actual average time for this task? (b) What is the normal time for this task if the employee worked at a 10% faster pace than is typical for adequately trained workers? (c) What is standard time for this task if allowances sum to 12%? (d) If the analyst then thought more carefully about his experiment and decided that the allowances needed to be increased to match the real (outside, not…
From a time study, the worker’s average observed time for a particular task is shown to be 5.6 minutes. The analyst feels the worker was performing their task, on average, about 25% faster than normal. What would be the resulting standard time assuming a 20% allowance for fatigue and personal needs?
An analyst has timed a metal-cutting operation for 50 cycles. The average time per cycle was10.40 minutes, and the standard deviation was 1.20 minutes for a worker with a performance ratingof 125 percent. Assume an allowance of 16 percent of job time. Find the standard time for thisoperation
Providence Assessment Center screens and trains employees for a computer assembly firm in Boston. The progress of all trainees is tracked, and those not showing the proper progress are moved to less demanding programs. By the tenth repetition, trainees must be able to complete the assembly task in 1 hour or less. Susan has just spent 5 hours on the fourth unit and 4.5 hours completing her eighth unit, while another trainee, Julie took 4 hours on the third and 2.8 hours on the sixth unit. Should you encourage either or both of the trainees to continue? Why? Present calculation steps. [Hint: For each trainee, 1) Determine the learning rate (%) – use doubling concept. 2) Calculate time for the 1st unit (T1) – use table, 3) Calculate time for the 10th Unit (T10) –use table] Susan Julie Learning rate (%) – doubling concept Time for the 1st unit Time for the 10th unit
You want to know the standard time of a welding process. The analyst has obtained the followingi information: average timed time - 1.30 minutes rhythm assessment - 110 fixed supplements - 5% variable supplements - 2% Determine the standard time, in minutes, of the welding process: a) 143 min b) 145 min c) 150 min d) 153 min
A hospital administrator thinks that the X-ray equipment is only in use about 20 percent of the time. What number of observations in a work sampling study would be needed to estimate the true percentage of time to within 5 percent with a confidence of 98 percent?
After training, Mary Fernandez, a computer tech-nician, had an average observed time for memory-chip tests of 12 seconds. Mary’s performance rating is 100%. The firm has apersonal fatigue and delay allowance of 15%.a) Find the normal time for this process.b) Find the standard time for this process.
An analyst has timed a metal cutting operation for 60 bikes. The average time per cycle was 10.30 minutes, and the standard deviation was 1:20 minutes for a worker with a performance rating of 120 percent. Assume an allowance of 16 percent of job time. Find the standard time for this operation.
After training, Mary Fernandez, a computer technician, had an average observed time for memory-chip tests of 15 seconds. Mary's performance rating is 105%. The firm has a personal fatigue and delay allowance of 12%. a) The normal time for this process = seconds (round your response to two decimal places). b) The standard time for this process =seconds (round your response to two decimal places).
Find out the standard time using the following data: Average time for machine elements = 6 min. Average time for manual elements = 3 min. Performance rating =110% Allowances = 11%
5. The manager of Asombrado Bounty Office, Charles Badillo, estimates his employees are idle 25%of the time. With that problem, how many work samples are needed to consider within 3%accuracy and have 95.45% confidence level. 6. At ASP Micro Manufacturing, Inc. workers press semiconductor into predrilled slots on printed-circuit boards. Determine the normal time of the operation in seconds. The elemental motions for normal time used by the company are as follows:• Reach 6 inches for semiconductors 10.5 TMU• Grasp the semiconductors 8.0 TMU• Move semiconductor to printed-circuit board 9.5 TMU• Position semiconductor 20.1 TMU• Press semiconductor into slots 20.3 TMU• Move board aside 15.8 TMU 7. The semiconductor used in Costin Calculator has 5 components with the consistency of 90%, 95%,98%, 90%, and 99%, respectively. How reliable is one product of calculator?
. Given the following information, determine the sample sizeneeded if the standard time estimate is to be within 5 percent ofthe true mean 97 percent of the time. Work Element Standard Deviation (minutes) Mean Observed Time (minutes)l 0.20 1.102 0.10 0.803 0.15 0.904 0.10 1.00

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