How much energy would be needed to freeze a 75.37-g sample of gallium at its freezing point of 29.7646 °C? Atomic Mass of Ga: 69.72 g/mol. Use the needed thermodynamic data from the given below: Heat of Fusion: 5.59 kJ/mol Heat of Vaporization: 256 kJ/mol A) -276.75 kJ -6.04 kJ (c) 276.75 kJ D) 6.04 kJ
How much energy would be needed to freeze a 75.37-g sample of gallium at its freezing point of 29.7646 °C? Atomic Mass of Ga: 69.72 g/mol. Use the needed thermodynamic data from the given below: Heat of Fusion: 5.59 kJ/mol Heat of Vaporization: 256 kJ/mol A) -276.75 kJ -6.04 kJ (c) 276.75 kJ D) 6.04 kJ
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Chapter11: States Of Matter; Liquids And Solids
Section: Chapter Questions
Problem 11.151QP
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The substance that constitutes everything in the universe is known as matter. Matter comprises atoms which in turn are composed of electrons, protons, and neutrons. Different atoms combine together to give rise to molecules that act as a foundation for all kinds of substances. There are five states of matter based on their energies of attraction, namely solid, liquid, gases, plasma, and BEC (Bose-Einstein condensates).
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When a chemical species is transformed into another chemical species it is said to have undergone a chemical reaction. It consists of breaking existing bonds and forming new bonds by changing the position of electrons. These reactions are best explained using a chemical equation.
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Transcribed Image Text:How much energy would be needed to freeze a 75.37-g sample of gallium at its freezing point of 29.7646 °C? Atomic Mass of Ga:
69.72 g/mol. Use the needed thermodynamic data from the given below:
Heat of Fusion: 5.59 kJ/mol
Heat of Vaporization: 256 kJ/mol
A) -276.75 kJ
-6.04 kJ
(c) 276.75 kJ
D) 6.04 kJ
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