Answered: How much ZnCl2 will make from 3 mol Zn…

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How much ZnCl2 will make from 3 mol Zn and 5 mol HCI Zn + 2HCI --> ZnCI2 + H2

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter5: Resonance

Section: Chapter Questions

Problem 5CTQ

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Question

How much ZnCl2 will make from 3 mol Zn and 5 mol HCI Zn + 2HCI --> ZnCI2 + H2

Expert Solution

Step 1

GIVEN:

Moles of Zn = 3 mol

Moles of HCl = 5 mol

To calculate: Amount of ZnCl₂ formed

Step 2

Given reaction is:

Zn + 2HCI -----> ZnCI₂ + H₂

First, we will find the LIMITING REAGENT.

According to the balanced reaction,

1 mol Zn reacts completely with 2 mol HCl.

So, 3 mol Zn will react completely with 2 x 3 mol HCl

= 6 mol HCl

But the given amount of HCl is 5 mol i.e. less than the required amount.

So, HCl act as the LIMITING REAGENT

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