How would I tell how and why this reaction changes in temperature and pressure? 4CO(g) + H2O(g) CH4 (g) + 3CO2 (g) ΔH°=-571.4kJ

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ChapterU5: Fire: Energy , Thermodynamics, And Oxidation-reduction
SectionU5.5: The Heat Is On: Specific Heat Capacity
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How would I tell how and why this reaction changes in temperature and pressure? 4CO(g) + H2O(g) CH4 (g) + 3CO2 (g) ΔH°=-571.4kJ
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