6. Calculate the formation enthalpy (AHorm) for benzene (C6H6). Is this reaction endothermic or exothermic? 2C,H6 + 1502 12CO2 + 6H20 AH° = -6535 kJ* AH orm values: O2: 0 kJ/mol - CO2: -393.5 kJ/mol - H2O: -285.8 kJ/mol MH = 1 g/mol, Mc= 12 g/mol, Mo = 16 g/mol, R = 0.08206 L.atm/mol.K or 8.314 J/mol.K

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Chapter6: Thermochemisty
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Problem 6.32QP: Shown below is a diagram depicting the enthalpy change of a chemical reaction run at constant...
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6. Calculate the formation enthalpy (AHorm) for benzene (C6H6). Is this reaction endothermic or exothermic?
2C,H, + 1502 -
12C02 + 6H20
AH° = -6535 kJ*
>
AH orm values: O2: 0 kJ/mol - CO2: -393.5 kJ/mol - H2O: -285.8 kJ/mol
MH = 1 g/mol, Mc= 12 g/mol, Mo = 16 g/mol, R = 0.08206 L.atm/mol.K or 8.314 J/mol.K
Transcribed Image Text:6. Calculate the formation enthalpy (AHorm) for benzene (C6H6). Is this reaction endothermic or exothermic? 2C,H, + 1502 - 12C02 + 6H20 AH° = -6535 kJ* > AH orm values: O2: 0 kJ/mol - CO2: -393.5 kJ/mol - H2O: -285.8 kJ/mol MH = 1 g/mol, Mc= 12 g/mol, Mo = 16 g/mol, R = 0.08206 L.atm/mol.K or 8.314 J/mol.K
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