HPro (aq) + OH-(aq) H2O (1) + Pro-(aq) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end of this "big change" reaction. (The LR concentration will be zero.) Using your values of HPrO and NaPro in the answer to the previous problem, plug into the Ka equation to solve for the value of [H*]. Calculate the pH of this final solution.

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Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 77E: Potassium hydrogen phthalate, known as KHP (molar mass = 204.22 g/mol), can be obtained in high...
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Please solve questions 7 & 8 based on the following data for [HPro], [NaOH], and [NaPro]. Thanks!

:-
the
end
O.100 M
(80.0+ 20.0)m2
[NaOH]
(80.0+20.0) mz
2.8 um
I Na Poo] =
O. 028 M
180.0+20.0) m2
Transcribed Image Text::- the end O.100 M (80.0+ 20.0)m2 [NaOH] (80.0+20.0) mz 2.8 um I Na Poo] = O. 028 M 180.0+20.0) m2
In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NaOH. (Na* is a
spectator ion and has been omitted.)
HPro (aq) + OH-(aq)
→ H2O (1) + Pro- (aq)
6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end
of this "big change" reaction. (The LR concentration will be zero.)
7) Using your values of HPrO and NaPro in the answer to the previous problem, plug into the Ka
equation to solve for the value of [H*].
8)
Calculate the pH of this final solution.
9)
Write the dissociation reaction for the weak base LiPro (Pro'-) in water.
10) Write the mass action expression for this equation, which is equal to K.
11) Since Kw = Ka × Kb., solve for the mathematical value of Kb.
12) Calculate the following values for a 0.138 M Ca(Pro)2 solution:
(a) the [OH] in a 0.138 M Ca(Pro)2 solution. (Use an "ICE" table)
(b) the pH of a 0.138 M Ca(Pro)2 solution.
Transcribed Image Text:In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NaOH. (Na* is a spectator ion and has been omitted.) HPro (aq) + OH-(aq) → H2O (1) + Pro- (aq) 6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end of this "big change" reaction. (The LR concentration will be zero.) 7) Using your values of HPrO and NaPro in the answer to the previous problem, plug into the Ka equation to solve for the value of [H*]. 8) Calculate the pH of this final solution. 9) Write the dissociation reaction for the weak base LiPro (Pro'-) in water. 10) Write the mass action expression for this equation, which is equal to K. 11) Since Kw = Ka × Kb., solve for the mathematical value of Kb. 12) Calculate the following values for a 0.138 M Ca(Pro)2 solution: (a) the [OH] in a 0.138 M Ca(Pro)2 solution. (Use an "ICE" table) (b) the pH of a 0.138 M Ca(Pro)2 solution.
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