ху — 2х — у +2 lim (K. y)-(1,2) X* + y² – 2x – 4y + 5

Q: LL im (x-2x+1) X→-1 2. Lim X'+3 X²-5 3-Lim Yx3X+6 X→-2

A: The limit of a function (expression ) is a value of that function (expression ) approaches as the…

Q: 7. et² -e-y² = }(e - e-1) lim %3D (x, y)→(1,1) x+y

A: To Determine: to prove  lim(x, y)→(1, 1)ex2-e-y2x+y=12(e-e-1) Given: we have a  problem based on…

Q: ev2x-y lim (x,y)→(3,2) x*-4x2 lim (x,y)¬(0,0) \x²+2y²,

A:

Q: Along the path z= e find 2. lim (2,4)→(1,0) y-4zy 3x-y-3

A: Here, we have to reduce this limit to a limit in a single variable by using the equation of curve.…

Q: x4-16y+ lim (x,y)¬(2,1) x²–4y2

A:

Q: 5y³ + 8y² 30. lim y→0 3y* – 16y²

A:

Q: dt 22. lim is x2 - 16 x-4 (A) – el6 (В) 2 e16 (C) 16el6 (D) nonexistent

A: Given: L=limx→4∫4xt2et2dtx2-16 For evaluating given limit, we use L hospital's rule According to L…

Q: (x²y3 - 5y2) lim (x, y) →(4, 2)

A: Given that, There is an expression of limit is following, lim(x, y)→(4, 2)(x2y3-5y2) We have to find…

Q: t2+3t+2 2. lim t--1 t2-t-2

A: To find the limit of the given function

Q: XVI+T(1-V2x+3) 7-6x+4x Compute lim

A:

Q: I can't find the limit.

A: Obtain the value of limit as follows:

Q: Show that 4z2 z2 +1 1 (b) lim- z→1(z – 1)3 (a) lim : 43B = 00; (c) lim = 00. - - z(I – 2) 0+2 I- 2…

A: We will use the simple calculations using some usual formulae to evaluate these limits.

Q: 1. lim (y – 2y+7) 2. lim (y² +5y–1) y→3 y2 3w - 4w+2 3. lim 3w – 2w+7 w² +1 | 4. lim w2 w -5 w-1

A:

Q: (a) im z6メ+5) メラ-S メ-25 lim メマロ Siho) tim 3メニ2 メ行ー

A:

Q: пу-1 lim y→0_2y² y(e2™y–1)

A: To evaluate limy→0(πy(e2πy−1)+πy−12y2) Rewrite the given expression:…

Q: Vx- 2 4. lim- x-2 x2 - 4 y-1 5. lim- Vy? +3 – 2

A: We can apply the limit to the expression by applying the limit as value for the variable in the…

Q: b. limx-3= In(x-2) %3D X-3

A:

Q: -xy س3: أحسب lim (x,y)→(0,0) x²+y² إضافة ملف

A: See the attachment

Q: Let h(x)

A: hx=x2,      x<23,       x=22,       x>2 Now, The left hand limit at x=2 is,…

Q: 4x +4 lim (2,y) (-1,2)` x² + 3xy – 3y2 + 3xy - 3y2

A:

Q: 2x lim(x,y)→(0,0) x² + x + y²

A:

Q: 22 – 4z + 4 Find limz→2 z2 – 4

A: limz→2z2-4z+4z2-4     =limz→2(z-2)2(z+2)(z-2)      =limz→2(z-2)(z+2       =2-22+2        =04…

Q: .2.4 lim (z,y)→(0,0) x² + y?

A: follow next step

Q: 2n j3 lim - 24n n00 j=1

A:

Q: Q 7 Find lim y+21y2 +71y + 51 y2-9

A: Consider the given limits

Q: -2ln(cosx lim, 0 ,2

A:

Q: z -1- i 2→1+i \ 22 – 2z + 2, 4. Find lim 2.

A:

Q: .2 lim (x,y)→(0,0) x² + y²

A: Consider the given: limx,y→0,0x2x2+y2Let y=mx

Q: -x²y² lim (x,4)→(0,0) (x³ + y³) e¯ x² + y²

A: Consider the given expression. limx,y→0,0x2+y3x2+y2e−x2y2 Put in the expression y=mx.…

Q: 8y – 24 lim y-3 2y - 6

A: Given limy→38y-242y-6

Q: (3 + 5y +7{ ) 2+y? 200 + y02 exists if lim r)(0.0)

A: This is a problem of multi variable calculus.

Q: -xy اس3: أحسب lim (x,y)→(0,0) x²+y2

A:

Q: *+xVア-2) lim )(4,16) x - Vy

A: Here we have lim(x,y)→(4,16)x2+xy-2yx-y

Q: Find the limit.

A: We have to find the given limit

Q: Q4/A/ Evahuate Vi+x -1- 2r-7x-15 5 3- lim,0 1- lim, o (tan 2x.csc 4x ) 2- lim,. x-5

A:

Q: 14. lim (y³ – 2y² + 3y – 4) y→-1

A: Hey, since there are multiple questions posted, we will answer first question. If you want any…

Q: 7 lim 『ストフ-2 X + 3 メy-3-

A:

Q: 19. lim x→2- x² – 4 eas y + 6 21. lim y→6+ y2 – 36 -

A: Given that limx→2- xx2-4 limx→6+y+6y2-36

Q: 2,,2 x²y² lim (x.y)→(0,0) x4 + 3y4

A:

Q: x*-16y* lim 14. (r,y)→ (0,0) x2 +4y2 xy 15. lim (x,y) (0,0) 3x² +2y2

A:

Q: /2х-у -2 lim (*) -2.0) 2х- у-4 3.) Evaluate 2x-y#4

A:

Q: 2. lim. (2y² + y+ 4) ソ→-1

A: Given: limy→-1(2y2+y+4)

Q: 3z+ 4y lim (2,0) +(0,0) 2z - 5y OA- OB OCo O D. Does not exist

A: Explained below

Q: 9 – y². |-(16 * 10)x – (4 * 10) lim . -] + lim y--33 + y x + 10 x--10

A: Given,            limy→-39 - y23 + y + limx→-10-16*10x-4*10x + 10

Q: (4 – x²y – V4 – x² .2 lim y→1 Y – 1

A: To find:limy→ 14-x2y-4-x2y-1

Q: x²+x5-2y lim (xy)-(3,9) %3D x-

A: Given limit lim(x,y)→(3,9)x2+xy-2yx-y

Q: (b) lim æ In(x² + y²) (x,y)→(0,0)

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.