Am I doing this correct?Determine the support reactions/reactions 48 kN/m323812-6671410 kN/m34P₁|0KN↓3B12P₁ = 160P₂=10(8)=8013 = 1/2 (36) 6) = 152.Bu Sm-725211.667/√82+5²-9.434tan18= 32 = 57.995tan oAT12=67.380SMA=0&++-By sin (67.38) (14) - By cos (67.38) (5) +.160 (11) + 803in (57.995) (4)+ 80 cos (57.995) (2.s) + 182 sin ($7.995) (2.667).152 cos (57.995) (1.667) =By = 176. 168 KN

Answered: i 48 kN/m32 в Анг 81 81 10 kN/m 3 4 P₁…

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i 48 kN/m32 в Анг 81 81 10 kN/m 3 4 P₁ [0KN ↓ ( - 3 B S 12 By Sm 211.667

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

Am I doing this correct? Determine the support reactions/reactions

48 kN/m32
3
81
2-6671
4
10 kN/m
3
4
P₁
|0KN
↓
3
B
12
P₁ = 160
P₂=10(8)=80
13 = 1/2 (36) 6) = 152.
Bu Sm
-725
211.667/
√82+5²-
9.434
tan
1
8
= 32 = 57.995
tan o
A
T
12
=67.380
SMA=0&+
+
-By sin (67.38) (14) - By cos (67.38) (5) +.160 (11) + 803in (57.995) (4)
+ 80 cos (57.995) (2.s) + 182 sin ($7.995) (2.667).
152 cos (57.995) (1.667) =
By = 176. 168 KN

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Step 3: Convert uniformly varying load into point load P3

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