I recovered 3 mL of cyclohexene, how many grams of water was produced in the reaction please show how? Cyclohexanol can attack the carbocation intermediate formed during the synthesis of cyclohexene. Draw this side product with the molecular formula C12H22O.
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I recovered 3 mL of cyclohexene, how many grams of water was produced in the reaction please show how?
Cyclohexanol can attack the carbocation intermediate formed during the synthesis of cyclohexene. Draw this side product with the molecular formula C12H22O.
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- 1-Pentanol to 1-bromopentane Chemicals: - 60ml Conc. Sulfuric Acid - 100ml Saturated Sodium bicarbonate - 65ml 1-Pentanol - 78g sodium bromide - Distilled water - 58.42g 1-Bromopentane 1-Pentanol Sodium Bromide Sulfuric Acid 1-Bromopentane Formula C5H12O NaBr H2SO4 C5H11Br MW (g/mol) 88.15 102.894 98.078 151.04 Density (g/mL) 0.811 3.21 1.84 1.218 Boiling point (*C) 138 1,396 337 130 NaBr(aq) + H2SO4(aq) -> NaHSO4(aq) + HBr(aq) CH3(CH2)4OH(aq) + H+ Br- (aq) CH3(CH2)4OH2 (aq) + Br-(aq) CH3(CH2)4OH2 (aq) + Br-(aq) CH3(CH2)4Br(aq) + H2O(aq) How do I calculate the percent yield and identify the limiting reagent?Given the following: Solutions Flask 1 Flask 2 Flask 3 0.04 M KI 25.0 mL 25.0 mL 12.5 mL 1% starch 5.00mL 5.00mL 5.00mL 0.03 M Na2S2O3 5.50 mL 5.50 mL 5.50 mL 0.05 M H2SO4 5.00 mL 5.00mL 5.00mL 0.08 M NaCl 0 0 10.0 mL and Solutions Beaker 1 Beaker 2 Beaker 3 0.04 M H2O2 25.0 mL 12.5 mL 25.0 mL deioinized water 0 12.5 mL 0 Following the procedure Run 1 is when Beaker 1 is added to Flask 1 and the timer is started giving the time recorded for the run in the table below. This is repeated with Beaker 2 and Flask 2 for Run 2 and finally Beaker 3 and Flask 3 for Run 3: The results for these runs are given below: Run Time (seconds) 1 35 2 66 3 72 Calculate the following for each run: the initial molarities of I- and H2O2 (from the solutions tables) the rates of reaction [I2]/time (calculate the [I2] from [S2O32-] and the reaction: I2(aq) + 2 S2O32-(aq) → 2I-(aq) + S4O62-(aq) Choose the correct rate law for this reaction from your calculations.…A student was given an unknown hydrate, which could be one of threepossibilities: magnesium sulfate heptahydrate, sodium dichromate tetrahydrate orbarium chloride dihydrate. Using the following data identify the unknown.Wt. of crucible/lid empty 39.46 gWt. of crucible/lid/hydrate sample 46.84 gWt. of crucible/lid/sample after heating 45.77 g
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