The switch in (Figure 1) has been open for a very long time. The switch is closed at tt = 0 s. Assume E = 170 V. At t = 0 s, what is the current in the 40 Ω resistor? At t = 0 s, what is the current in the 10 Ω resistor?
Ohm's law
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Path of Least Resistance
In a series of alternate pathways, the direction of least resistance is the actual or metaphorical route that offers the least resistance to forwarding motion by a given individual or body.
The switch in (Figure 1) has been open for a very long time. The switch is closed at tt = 0 s. Assume E = 170 V.
At t = 0 s, what is the current in the 40 Ω resistor?
At t = 0 s, what is the current in the 10 Ω resistor?
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I understand where part A comes from, but I'm having a hard time making sense for process B and C. I thought I would have to get the potential difference across the first resistor by multiplying I60ohm times the first resistor, divide that potential by Rtotal parallel (8 ohm). Can you break down the process a little bit? Thank you
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