I.Give the thermochemical data below, find the change in enthalpy for thefollowing reactions:NO 2(9)AH= ?1.) NO(9) + ½ 02(9)NO 2(g)AH= 33.18 kJ½ N%9) + O2(g)AH = -90.37 kJNO (g)½ Nzg)+ % O2g)+ ½2(g)AH = ?CIF3(9)2.) CIF(9) + F2(9)AH = - 49.4 kJOz19) + 2F2(9)+ 2F2(g)20F2(9)AH= 205.6 kJCl,O (9) + OF2(9)2CIF(6) + Oz19)+ O21g)(g)AH = 266.7 kJ½ Cl,0,) + 3/2 OF21)CIF33(g)

∆H of a reaction is the amount of heat released in the reaction.

I. Give the thermochemical data below, find the change in enthalpy for the following reactions: NO 2(9) AH= ? 1.) NO(9) + ½ O2(g) (6), AH= 33.18 kJ NO 219) + O2(g) ½ N219) AH = -90.37 kJ NO (9) ½ N1g) + ½ 02(g)

I. Give the thermochemical data below, find the change in enthalpy for the following reactions: NO 2(9) AH= ? 1.) NO(9) + ½ O2(g) (6), AH= 33.18 kJ NO 219) + O2(g) ½ N219) AH = -90.37 kJ NO (9) ½ N1g) + ½ 02(g)

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter9: Energy And Chemistry

Section: Chapter Questions

Problem 9.53PAE: 9.53 Using these reactions, find the standard enthalpy change for the formation of 1 mol of PhO(s)...

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Question

I.
Give the thermochemical data below, find the change in enthalpy for the
following reactions:
NO 2(9)
AH= ?
1.) NO(9) + ½ 02(9)
NO 2(g)
AH= 33.18 kJ
½ N%9) + O2(g)
AH = -90.37 kJ
NO (g)
½ Nzg)+ % O2g)
+ ½
2(g)
AH = ?
CIF3(9)
2.) CIF(9) + F2(9)
AH = - 49.4 kJ
Oz19) + 2F2(9)
+ 2F2(g)
20F2(9)
AH= 205.6 kJ
Cl,O (9) + OF2(9)
2CIF(6) + Oz19)
+ O21g)
(g)
AH = 266.7 kJ
½ Cl,0,) + 3/2 OF21)
CIF3
3(g)

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