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I. Identify the oxidation number by writing the number on top of each element on the given equation. And write the half reaction for reduced and oxidized reaction. CIO3 + 1* = CI + 12 II. Identify the oxidation number by writing the number on top of each element on the iven equation. And write the half reaction for reduced and oxidized reaction. Sn+2 +2 Fe+3 = Sn+4+2Fe+2

I. Identify the oxidation number by writing the number on top of each element on the given equation. And write the half reaction for reduced and oxidized reaction. CIO3 + 1* = CI + 12 II. Identify the oxidation number by writing the number on top of each element on the iven equation. And write the half reaction for reduced and oxidized reaction. Sn+2 +2 Fe+3 = Sn+4+2Fe+2

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section3.5: Oxidatino-reduction And Electron Transfer
Problem 3.11CE
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I. Identify the oxidation number by writing the number on top of each element on the given equation. And write the half reaction for reduced and oxidized reaction. CIO3 + 1* CI + 12 II. Identify the oxidation number by writing the number on top of each element on the given equation. And write the half reaction for reduced and oxidized reaction. Sn+2+2 Fe+3 = Sn+4+2 Fe +2
Transcribed Image Text:I. Identify the oxidation number by writing the number on top of each element on the given equation. And write the half reaction for reduced and oxidized reaction. CIO3 + 1* CI + 12 II. Identify the oxidation number by writing the number on top of each element on the given equation. And write the half reaction for reduced and oxidized reaction. Sn+2+2 Fe+3 = Sn+4+2 Fe +2
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