  Identify the acid and conjugate base in each reaction. Calculate the pKA for each acid. List them in order from the strongest to weakest acid. The acid-ionization constants, KA, at 25°C are provided for each.C6H5OH + H2O Û H3O+ + C6H5O-, KA = 1.2589254 x 10-10CH3CO2H + H2O Û H3O+ CH3CO2-, KA = 1.5848 x 10-5CF6CO2H+H2O Û H3O+ + CF6CO2-, KA = 0.6309

Question

Identify the acid and conjugate base in each reaction. Calculate the pKA for each acid. List them in order from the strongest to weakest acid. The acid-ionization constants, KA, at 25°C are provided for each.

1. C6H5OH + H2O Û H3O+ + C6H5O-, KA = 1.2589254 x 10-10
2. CH3CO2H + H2O Û H3O+ CH3CO2-, KA = 1.5848 x 10-5
3. CF6CO2H+H2O Û H3O+ + CF6CO2-, KA = 0.6309
Step 1

Conjugate acid-base pair are considered differ only by H+ ion. Acid form corresponding conjugate base by losing H+ ion while base form corresponding conjugate acid by gaining H+ ion. In an acid-base reaction, the chemical reaction can be written as follows:

Step 2

1. C6H5O- is considered conjugate acid for base C6H5OH while H3O+ is considered conjugate acid for base H2O.

2. CH3CO2- is considered conjugate base for acid CH3CO2H while H3O+ is considered conjugate acid for base H2O.

3. CF6CO2- is considered conjugate acid for acid CF6CO2H while H3O+ is considered conjugate acid for base H2O.

Step 3

Ka is considered the acid dissociation constant while pKa is simply the -log...

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