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Q: Delta H degrees and Delta S degrees for a reaction are –11.7 kJ/mol and –105 J/mol K, respectively.…
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- Suppose a certain small bird has a mass of 30 g. What is the minimum mass of glucose that it must consume to fly to a branch 10 m above the ground? The change in Gibbs energy that accompanies the oxidation of 1.0 mol C6H12O6(s) to carbon dioxide and water vapour at 25 °C is -2828 kJ.Give an example to show the difference between the three types of specification of a system, the macrostate, the distribution, and the microstate?Coiled coils are protein domains that lead to the formation of multimers (dimers,trimers, tetramers, etc.). They are found in a wide range of proteins. Here we willconsider the trimerization reaction. We may write the chemical equilibrium as3 M(aq) ⇄ T(aq)where M and T represent, respectively, the monomer and trimer species. Given that∆rG0 = −25.00 kJ mol−1 at 37 0C (with the standard state the normal one for reactionsin solution, namely c0 = 1.0 mol dm−3):A) What is the equilibrium constant for the formation of the trimer at 37 0C? B) Suppose that in a particular experiment at 37.00 0C the initial concentrations ofthe monomer if [M]0 = 2.00×10−2 µM and the initial concentration of the trimeris also [T]0 = 2.00 × 10−2 µM. What is ∆rG for the formation of the trimer atthe specified temperature? C) For the conditions given in part (B) will trimers spontaneously convert to monomers?Give a very short justification of your answer. D) Suppose that ∆rH0 and ∆rS0 are independent of the…
- The change in Gibbs energy that accompanies the combustion of C6H12O6(s) to carbon dioxide and water vapour at 25 °c is -2828 kJ mol-1. The potential energy of an object of mass m at a height h, relative to that at the Earth's surface is given by mgh, where g = 9.81 m s-2 is the acceleration of freefall. How much glucose does a person of mass 65 kg need to consume to climb through 10m?Without carrying out an explicit calculation, explain there lative values of the standard molar entropies (at 298 K) of the following substances: (a) Ne(g) (146 J K-1 mol-1) compared with Xe(g) (170 J K-1 mol-1), (b) H2O(g) (189 J K-1 mol-1) compared with D2O(g) (198 J K-1 mol-1), (c) C(diamond) (2.4 J K-1 mol-1) compared with C(g raphite) (5.7 J K-1 mol-1).For a certain constant-pressure process, the change in Gibbs energy was found to fit the expression: G/J = -20+ 10(T/K). What are H and S for the process?
- Consider the synthesis of sulphur trioxide from its elements at 25oC:1/4 S8 (s) + 3O2(g) → 2SO3 (g) Thermodynamic Data: Species ∆fHo(kJ/mol)(at 298.15 K) So (J/K.mol)(at 298.15 K) ∆fGo (kJ/mol)(at 298.15 K) S8(s) 102 431 50 O2(g) 205 SO3 (g) -396 257 -371 2.1.1 Calculate ∆rGo , using only Gibbs energy values.2.1.2 Calculate the equilibrium constant, K, at 25oC for this reaction 2.1.3 Calculate ∆Ssurr for the synthesis of sulphur trioxide at 25oC 2.1.4 Calculate ∆Suniv for the synthesis of sulphur trioxide at 25oC 2.1.5 Calculate ∆rG at 25oC when the reaction mixture consists of 2.3 mg of S8, 3.5 bar O2 and 1.50 bar SO3. Please calculate 2.1.2Consider the synthesis of sulphur trioxide from its elements at 25oC:1/4 S8 (s) + 3O2(g) → 2SO3 (g) Thermodynamic Data: Species ∆fHo(kJ/mol)(at 298.15 K) So (J/K.mol)(at 298.15 K) ∆fGo (kJ/mol)(at 298.15 K) S8(s) 102 431 50 O2(g) 205 SO3 (g) -396 257 -371 2.1.1 Calculate ∆rGo , using only Gibbs energy values.2.1.2 Calculate the equilibrium constant, K, at 25oC for this reactionFor the complete neutralization reaction between a 1 M strong acid and a 1 M strong base of equal initial volumes that is marked by a temperature rise, the entropy of neutralization is positive (ΔSrxn > 0) whereas the Gibbs free energy is negative (ΔGrxn < 0). Is this true or false? Please explain.
- 1.Thermodynamics of polymerization determines the position of the equilibrium between polymer and monomer(s). What is the impact of thermodynamic in polymers? Give examples to support your answer. 2.Explain the significance of Gibbs energy in thermodynamics of polymerization. Show the equations to support your answer.How does the Gibbs energy of a pure material change with increasing the temperature at constant pressure? Provide the appropriate equations as well!Derive a formula for the molar Gibbs free energy change of a closed system at constant temperature if the system obeys the equation of state PV = nRT + nCP where C is a constant.