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A sample of a liquid from an unlabeled bottle was subjected to analysis: MS showed that M+ has m/z of 89 and IR displayed bands at 2995-2840 cm-1, 1562 cm^-1, and 1425 cm^-1. Identify the functional group in the molecule and provide two possible structures.
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- which of the following compounds present bands in the IR spectrum at 3000-3500 cm-1, 1750 cm-1 and 1220 cm-1.Which of the following compounds can have a broad absorbance band near 3300 cm-1 and 1650 cm-1?The base peak in the mass spectrum of 2,2,5,5-tetramethylhexane (molecular mass = 142) is at m/z = 57, which corresponds to a composition of C4H9. Suggest a structure for the fragment that accounts for this peak and offer a reason for why this fragment is so abundant.
- You have a Compound A which over time decomposes into Compound B. By performing a UV-Vis test at a length of 600 nm wave to a solution of A at a concentration of 120 mg/L, gave 0.98 transmittance and at 520 nm gave 0.61, this in a cell 1 cm long; The same test was made to compound B at a concentration of 20 mg/L, resulting in 0.25 of transmittance at 600nm and 0.72 transmittance at 520 nm. 2.5 grams of sample were taken and diluted in 25 milliliters, and UV spectroscopy was performed in a 1cm cell, giving as result at 600 nm 0.52 transmittance and at 520 nm 0.44. What is the percent decomposition in grams of Compound A?C8H8O produces an IR spectrum with 3063, 1686, 1646 cm signals. HNMR is a singlet at 2.6ppm (3H), and multiplet at 7.5 (5H). What is the productCalculate the HDI of each FM and propose 2structures for two molecules that are isomers.Specify what the indicated absorption (s) shouldbe to.a.C7H15NO with strong absorptions in 3400, 3270and 1670, 1390, and 1370 cm-1b. C6H10O with absorptions in 2065 (m), 1685 (f),1650 (m) and 970 (f) cm-1c. C9H12O, with absorptions in 1600 and 1500 and1245 cm-1.
- MS: m/z=148 (M,100%),149 (11%) IR (liquid film): 3077‐2835 (multitude of weak peaks) 1640(m),1611(m),1511(s),1301(m),1247(s),1176(s),1038(s),922(m),914(m) and 810(m)cm^-1 There are no absorptions in the 3100-‐4000cm^-1 region of the spectrum. (m=medium absorption, s=strong absorption). Choose (circle) the best structure for estragole (W) from the four possible structures (1-4)shown below. Explain briefly how you eliminated each of the incorrect structures for W.The DPD colorimetric method is used to determine the amount of residual chlorine in the sample. In this method, the free chlorine in the sample oxidizes the colorless amine N,N-diethyl-p-phenylenediamine to a colored compound that absorbs strongly at 520 nm. The analysis of a set of calibration standards gave the following results:ppm Cl2 Absorbance0.00 0.00310.50 0.12321.00 0.32411.50 0.54382.00 0.76422.50 0.95513.00 1.1565A 10.00 mL water sample from a public water supply was diluted to 250 mL and analyzed for free chlorine residual, giving an absorbance of 0.3210.A. Find the equation of the line.B. What is the molar absorptivity of Cl2 (FW = 70.9) at 250 nm?C. Calculate the free chlorine residual of the sample as ppm Cl2.D. Calculate ppm BaCl2 (FW = 208.2)?Sally obtains a standard calibration curve for their assigned food dye by plotting absorbance versus concentration (in M) of known solutions and finds the following slope and intercept: y = 1.646x + 0.026 Note: Copying and/or posting this or other questions without the express written permission from Dr. Burke and the Department of Chemistry & Biochemistry at the University of Delaware is a violation of intellectual property copyright law. Sally finds that her original Kool-aid sample is too concentrated, so they dilute it by transferring 13.00 mL of the original Kool-aid sample into a new container and diluting to a total volume of 37.00 mL. If the absorbance of the dilute Kool-aid sample at the appropriate wavelength for their assigned dye is 0.950, determine the concentration (in M) of the assigned food dye in the original Kool-aid sample. Report your answer with three places after the decimal.
