Identity of metal Mass of metal, (g) Copper 31.715 Trial 1 Mass of Styrofoam® cup and water, (g) 110.850 Mass of Styrofoam® cup, (g) 9.925 Trial 2 88.845 10.385 g Mass of water, (g) 100.925 78.46 Initial temperature of metal (Temperature of the boiling water) 90°C 98.5°C Initial temperature of water in cup, 22.5°C 22.5°C Final temperature of water and metal 25°C Specific heat of metal, (cal/g° C) Average specific heat of metal, (cal/g 33% 25°C 2.95% C) Calculations: ATwater Tf- Ti water °C ATmetal Tf-Ti metal ос = Qwater (1.00 cal/g°C) x ( _g H2O) x (°C) = cal Qmetal = - Qwater Cmatel Ometal/mmetal X ATmetal=- cal/[C g)x( °C)] = _cal/g°C
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
![Identity of metal
Mass of metal, (g)
Copper
31.715
Trial 1
Mass of Styrofoam® cup and water, (g)
110.850
Mass of Styrofoam® cup, (g)
9.925
Trial 2
88.845
10.385 g
Mass of water, (g)
100.925
78.46
Initial temperature of metal
(Temperature of the boiling water)
90°C
98.5°C
Initial temperature of water in cup,
22.5°C
22.5°C
Final temperature of water and metal
25°C
Specific heat of metal, (cal/g° C)
Average specific heat of metal, (cal/g
33%
25°C
2.95%
C)
Calculations:
ATwater Tf- Ti water
°C
ATmetal Tf-Ti metal
ос
=
Qwater (1.00 cal/g°C) x (
_g H2O) x (°C) =
cal
Qmetal = - Qwater
Cmatel
Ometal/mmetal X ATmetal=-
cal/[C
g)x(
°C)] =
_cal/g°C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07f23d12-9e67-4de5-b399-6715d1bbadc0%2Fe07b381f-7b38-4d13-a331-7c0b46b01c0d%2Fv9nnxl_processed.png&w=3840&q=75)
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