# If 0.460 mol of liquid CS2 and 0.500 mol of gaseous O2 are reacted stoichiometrically according to the balanced equation, how many moles of gaseous CO2are produced?CS2(l) + 3O2(g) → CO2(g) + 2SO2(g) Molar Mass (g/mol)CS276.143O231.998CO244.009Density (g/mL)CS21.26    Molar Volume (L)22.4 at STPGas Constant(L.atm.mol-1.K-1)0.0821

Question
Asked Dec 3, 2019
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 If 0.460 mol of liquid CS2 and 0.500 mol of gaseous O2 are reacted stoichiometrically according to the balanced equation, how many moles of gaseous CO2are produced?

CS2(l) + 3O2(g) → CO2(g) + 2SO2(g)

Molar Mass (g/mol)
 CS2 76.143 O2 31.998 CO2 44.009
Density (g/mL)
 CS2 1.26
Molar Volume (L)
 22.4 at STP
Gas Constant
(L.atm.mol-1.K-1)
 0.0821
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## Expert Answer

Step 1

Given:

Moles of CS2 = 0.460 mol.

Moles of O2 = 0.500 mol.

Balanced chemical reaction is given by,

CS2(l) + 3O2(g) → CO2(g) + 2SO2(g)

Step 2

Identifying limiting reactant:

Number moles of CS2 reacting= 0.460/1 = 0.460 mol.

Number of moles of O2 react...

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