If 4.50 moles of NO₂ are allowed to react with excess H₂O according to the balanced equation: 3NO2 + H₂O 2HNO3 + NO, the amount (in moles) of HNO3 formed will be: O 3/2 x 4.50 O 2.00 O 2/3 x 4.50 O 4.50 OK

Chemistry for Engineering Students
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Chapter3: Molecules, Moles, And Chemical Equations
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If 4.50 moles of NO2 are allowed to react with
excess H₂O according to the balanced equation:
3NO2 + H₂O 2HNO3 + NO, the amount (in
moles) of HNO3 formed will be:
O 3/2 x 4.50
O 2.00
O 2/3 x 4.50
O 4.50
OK
Transcribed Image Text:If 4.50 moles of NO2 are allowed to react with excess H₂O according to the balanced equation: 3NO2 + H₂O 2HNO3 + NO, the amount (in moles) of HNO3 formed will be: O 3/2 x 4.50 O 2.00 O 2/3 x 4.50 O 4.50 OK
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