If a 0.4340g sample of methenamine were treated in the usual way with 25mL of 0.6500N H2SO4 and 9.45mL of 0.45000 N NaOH was required in the back titration, what would be the percent of Methnemine in the sample?
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If a 0.4340g sample of methenamine were treated in the usual way with 25mL of 0.6500N H2SO4 and 9.45mL of 0.45000 N NaOH was required in the back titration, what would be the percent of Methnemine in the sample?
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- What is the reaction for the 2-methylpropan-1-amine(Isobutylamine) titration with hydrochloric acid? Explain how to solve such tasks. ThanksThe Kjeldahl procedure was used to analyze 244 µL of a solution containing 38.1 mg protein/mL. The liberated NH3 was collected in 5.00 mL of 0.0375 M HCl and the remaining acid required 5.98 mL of 0.00998 M NaOH for complete titration. What is the weight percent of nitrogen in the protein?An unknown sample containing mixed alkali (naoh, nahco3, or na2co3) was analyzed using the double flask method. a 250 mg sample was dissolved in 250 ml co2 free water. a 20.0 ml aliquot of this sample required 11.3 ml of 0.009125 m hcl solution to reach the phenolphthalein end point. another 29.0 ml aliquot of the sample was titrated to the bromocresol green endpoint using 31.1 ml of the standard acid. how many millimoles of the components are there in the original solid sample
- John wanted to determine the protein content of his blood. To do so, he obtained 1.00 mL of blood, and diluted it to 10.00 mL. From that solution, he subjected 1.00 mL to Kjeldahl analysis. After digestion, the liberated NH3 was distilled in a flask containing exactly 25.00 mL of 0.0150 M H3BO3. Titration requires 5.85 mL of standard 0.0150 M NaOH to reach the desired endpoint. If a typical blood sample contains 15.45 g N per 100 g protein, calculate the protein content (in g/mL) in the sample of John’s blood.In the preparation of a standard stock solution for protein analysis, 50 mg of bovine serum albumin (BSA) was dissolved in deionized distilled water to a final volume of 10 mL. What is the weight of BSA in 0.60 mL stock solution?John wanted to determine the protein content of his blood. To do so, he obtained 1.00 mLof blood, and diluted it to 10.00 mL. From that solution, he subjected 1.00 mL to Kjeldahl analysis. After digestion, the liberated NH3 was distilled in a flask containing exactly 25.00 mL of 0.0150 M H3BO3. Titration requires 5.85 mL of standard 0.0150 M NaOH to reach the desired endpoint. If a typical blood sample contains 15.45 g N per 100 g protein, calculatethe protein content (in g/mL) in the sample of John’s blood.
- The Kjeldahl procedure was used to analyze 256 L of a solution containing 37.9 mg protein/mL. The liberated NH3 was collected in 5.00 mL of 0.033 6 M HCl, and the remaining acid required 6.34 mL of 0.010 0 M NaOH for complete titration.A 0.5843-g sample of a plant food preparation was analyzed for its N content by the Kjeldahl method, the liberated NH3 being collected in 50.00 mL of 0.1062 M HCl. The excess acid required an 11.89 mL back-titration with 0.0925 M NaOH. Express the results of this analysis in terms of (a) %N (b) %urea, H2NCONH2 (c) %(NH4)2SO4 (d) %(NH4)3PO4Calculate the number of grams of oxalic acid dihydrate (M.W. = 126.1g/mol) necessary to react with 35 mL of the 0.1 M NaOH solution. Showall your calculations. Note: 35 mL is the approximate volume of NaOHsolution that needs to be used in the titration in order to obtain theprecision desired in this experiment.
- What weight of strontium acetate containing 99% Sr(CH3COOH)2.½H2O must be used as sample in an assay according to the general method for alkali salts of organic acids if, after treatment of the ash with 50.00 ml of 0.5162 N hydrochloric acid, it is desirable to consume 30.00 ml of 0.4675 N sodium hydroxide in the back titration?The distribution ratio of iodine between an organic solvent and water is 8.00. If 50.0 mL of0.100 M aqueous iodine is shaken with 200 mL of the organic solvent until equilibrium isreached, how many milliliters of 0.0600 M Na2S2O3 is required to titrated a 25.0 mL aliquot ofthe organic phase?a) 0.132g of a pure carboxylic acid (R-COOH) was dissolved in 25.00mL of water and titrated with 0.120M of standardised NaOH solution. A volume of 14.80mL was required to reach the endpoint of the titration.Identify the carboxylic acid.b) A 0.670g sample of barium hydroxide is dissolved and diluted to the calibration mark in a 250.0mL volumetric flask. It was found that 11.56mL of this solution was needed to neutralise 25.00mL of nitric acid solution. Calculate the molarity of the nitric acid solution. Write a chemical equation in your response.c) One student's results are given below:- Concentration of NaOH(aq) = 0.110M- Volume of undiluted vinegar = 10.00mL- total volume of diluted vinegar = 100.00mL- volume of diluted vinegar used in each titration = 20.00mL- Avg. titre of NaOH(aq) = 15.35mLBased on these results, calculate the concentration, in mol L-1, of acetic acid in the undiluted vinegar solution.
