If a sample of lithium contains 2.50x10* atoms of lithium-7 and 2.00×10 atoms of lithium-6, what is the percentage of lithium-6 atoms in the sample?
Q: 16.The atomic masses of * Cl (75.53 percent) and "Cl (24.47 percent) are 34.968 and 36. 956 a.m.u.,…
A: Introduction: Chlorine belongs to group 17 elements with atomic number 17 and mass 35.45 amu. Group…
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A: CCl4 is carbon tetrachloride. Mass ratio of Cl:C is 11.8:1 It means 11.8 g Cl per 1 g C
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A: Given: Mass of silicon=1.00 g Mass of 1 mole of silicon=28.0855 g
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A: A mole represents 6.022x1023 particlesThe 6.022x1023 Number is also known as Avogdro's Number .It…
Q: How many grams of copper that consists of 1.54 x 1024 atoms of copper?
A: To convert atoms to grams, Step I - Convert atoms to moles 1 mol = 6.022 × 1023…
Q: How much does 4.28 x 10 21 atoms of Nickel weigh?
A: We know that, one mole of any substance contains 6.022 × 1023 atoms. We can determine the weight by…
Q: what is the mass, in grams, of 3.01 x10^23 copper atoms
A: Number of copper atoms = 3.01 × 1023 We need to determine mass of copper.
Q: Calculate the mass, in kg, of sample. 8.15x10^27 nickel atoms
A: The mass of sample. 8.15x10^27 nickel atoms is to be calculated
Q: a. 1.51 x 1015 atoms of Si to mol of Si
A: Given number of atoms can be easily calculated to moles by using avogadro number.
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A:
Q: What is the mass of 4.97×1021 platinum atoms?
A: Mass has many units. Its SI unit is Kg. On atomic level, atomic mass unit, molar mass, molecular…
Q: Suppose that atomic masses were based on the assignment of a mass of 12.000 g to 1 mol of carbon,…
A: SOLUTION: Step 1: One Dalton is defined as one-twelfth the mass of one mole of carbon-12 isotopes.…
Q: How many grams would 4.15 x 1021 atoms of Pb weigh?
A: Answer
Q: A 20.0 g sample of an element contains 3.89 x 1023 atoms.
A: Given:- Number of atoms = 3.89 × 1023atoms Mass of sample = 20.0g
Q: You are given 1.0g samples of Iron, Silicon, and Lithium. Which of the three samples will contain…
A: Given: 1 g sample of Iron, silicon and lithium To find: Sample containing largest number of atoms…
Q: Verify that the atomic weight of lithium is 6.94, given the following information: 6 Li, mass =…
A: Given, Percent abundance of 6Li = 7.50% Mass of 6Li = 6.015121 amu Percent abundance of 7Li =…
Q: Calculate the relative percent abundance of 6Li given the following information: mass of 6Li =…
A: Given mass of 6Li = 6.01512 umass of 7Li = 7.01699 u
Q: What is the mass in grams of 6.022 * 1023 N atoms of mass 14.01 amu?
A: To determine the mass in grams of 6.022x1023 N atoms of mass 14.01 amu Given that: Mass of each atom…
Q: How many moles of silver are 1.8x10^20 atoms of silver ?
A:
Q: If the density of lead is 11.34 g / a.m., how many atoms are there in a piece of lead 2.5 cm wide,…
A: To calculate the number of atoms in the sample, we must have the number of moles of the substance.…
Q: How many hydrogen atoms are there in 8.75 g of C,H,NO,? Select one: a. 23 4.79x 10 b. 3.22x 1023 с.…
A: Given: Mass of C2H7NO2 = 8.75 g Molar mass of C2H7NO2 = 77.08 g/mol
Q: What mass of nickel would contain 5.66 x 1021 atoms?
A:
Q: What is the mass of 6.02 x 1023 Cu atoms?
A:
Q: 28) 8.42 x 1027 atoms of tin 29) 6.39 x 1018 atoms of sulfur
A: Given 8.42 × 1027 atoms of tin 6.39 × 1018 atoms of sulfur 5.99 × 1030 molecules of SiO2
Q: Calculate the mass, in kg, of sample. 5.48x10^29 lithium atoms
A: Molar mass of lithium is 6.94 g/mol 6.023 x 1023 atoms have mass = 6.94 g of lithium
Q: The mass of an atom of hydrogen is 1.673 x 10-24 g. How many atoms are in a 10.8 g sample of…
A: Since mass of 1 H atom = 1.673 x 10-24 g Hence assuming in 10.8 g sample of hydrogen we have n…
Q: White sand is made of silica (silicon dioxide, or SiO2), which has a density of 2.20 g/cm3. How many…
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Q: Calculate the mass, in kg, of sample. 7.55x10^26 cadmium atoms
A:
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A: we have a penny of mass 3.10 gram. and it's also mentioned that in a modern penny the percentage of…
Q: If there are 8.59 x 1022 molecules of NaCl in a salt shaker, what is the mass of NaCl?
A:
Q: How many moles are there in 2.17 x 1023 atoms of Au?
A:
Q: How many helium atoms are there in a helium balloon containing (1.8x10^0) kg of helium?
A: Given :- mass of He = 1.8 × 100 kg To calculate :- number of atoms of He number of moles =…
Q: What is the mass of one atom of I? O 6.641 x 10-23 g O 4.745 x 10-22 g O 2.107 x 10 22 g O 3.443 x…
A: To determine the mass of 1 atom of I, do the following : 1) Determine molar mass of the substance.…
Q: How many moles of neon would there be in 7.59 x 1025 neon atoms?
A: Given that : Atoms of neon = 7.59 x 1025 atoms Moles of neon =?
Q: What mass (g) would 4.10 x 10^16 atoms Mg have
A: We have to determine the mass of 4.10×1016 atoms of Mg.
Q: White sand is made of silica (silicon dioxide, or SiO2), which has a density of 2.20 g/cm3. How many…
A: The question is based on mole concept. We have been given diameter of the silicon atom. we have to…
Q: 13) If you measured a mass of 245 g of Iron, you would have atoms Fe. * O 4.39 O 2.64e24 O 8.24e27 O…
A: To calculate the number of atoms or molecules of an element we must have the number of moles of that…
Q: 6. What is the mass of 6.20 x 1025 atoms of sulfur?
A: We have 6.2*1025 atoms of sulphur , we have to calculate the mass of given atoms of sulphur.
Q: White sand is made of silica (silicon dioxide, or SiO2), which has a density of 2.20 g/cm3. How many…
A: Given : Density of silica = 2.20 g/cm3 And diameter of grain of sand = 0.455 mm
Q: Calculate the number of atoms in a 2.33 x 10' g sample of silicon.
A: Avogadro’s number or Avogadro’s constant relates the molar mass and the physical mass of an element,…
Q: Calculate the number of atoms in a 4.06 x 10 g sample of calcium. number of atoms:
A: Given: The mass of the sample of calcium (Ca) is 4.06 x 103. The molecular weight of calcium (Ca) is…
Q: How many atoms of hydrogen are there in a sample of (9.60x10^2) grams of CH4(g)?
A: The number of moles of a substance is defined as the ratio of mass to molecular mass. So, The…
Q: What is the mass of 4.50 x 1044 Cu atoms?
A: Given :- number of Cu atoms = 4.50 × 1022 atoms To calculate :- mass of Cu (in g)
Q: Calculate the mass, in kg, of sample. 1.22x10^27 manganese atoms
A:
Q: How many grams of lithium are in 8.52 x 1023 atoms?
A: 1 mole of any species contains Avogadro's number of atoms or molecules. i.e, 6.023 × 1023 Molar…
Q: How many moles of gold are 8.5 x 1024 atoms of gold?
A:
Q: 1. How many moles of tungsten atoms are there in 4.8 x 1025 atoms of tungsten?
A: Since you have asked multiple question,as per our company guidelines we are supposed to answer the…
Q: An element X has two common isotopes: X-57 and X-59. If the average atomic mass of element X is…
A: An element has two isotopes : X-57 and X-59 Average Atomic mass = 58.876 amu
Q: Find the mass of 2.45 X 1023 molecules of Ca(OH)2? Use: Ca = 42.0g, H = 1.25g and O = 15.7g as…
A:
Q: What is the mass of 4.91×1021 platinum atoms?
A: Given:Number of platinum atoms = 4.91×1021.Molar mass of platinum = 195.084 g/mol.
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- lt ls desired t0 c0ncentrate a 6% KNO3 s0luti0n in water t0 20% KNO3 s0luti0n. 7000 kg of pr0duct liqu0r is t0 be needed/hr. H0w much s0luti0n must be charged? H0w much water is evap0rated?4. Ksp=4.1x10-36 for Pb3(AsO4)2Calculate Eofor Pb3(AsO4)2(s) + 6e- 3Pb(s) + 2AsO43-Pb2+ +2e- Pb(s) Eo= -0.126 VThere's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
- There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…Ee.5. With explanation please....Show all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdk
- Please answer super fast and answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.4665.61 x 10^-12 is the kspPlease answer fast it’s very important and urgent I say very urgent so please answer super super fast please For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466