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A: Topic:- application of derivatives

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Q: Use f(x) = 5x - 6 and g(x) = 4 - x2 to evaluate the expression. (a) f(g(0)) 25x – 30 (b) g(f(0)) -12...

A: f(x) = 5x - 6 g(x) = 4 -x2 now  f(g(0)) = f(4-x2 ) = 5(4-x2 ) -6                           =  20 -5x...

Q: Can you please answer both

A: see below the answer and calculation

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A: Given:      y = 2x2 - 3  Points : x = -2 , x = 1

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Q: Determine the point/s of discontinuity, if there is any, and the type of discontinuity at that point...

A: G(x) = (x2 -3x -4)/(x -4)     if x is not equal to 4         =  5                           if x =4 ...

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A: Reupload other questions according to bartleby guidelines

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A: topic - definite integral

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