If in the roll of a die, event A suggests that a single role will produce a score of 3 or more, and event B suggests that a single role will produce a score of 2 or less, find the better estimate. ⇒ In a die, we know there are six possible scores, that is, {1, 2, 3, 4, 5, 6} For event A, the possible outcomes are {3, 4, 5, 6}, and for event B, the possible outcomes are {1, 2} ∴ P(A)=46=23and, P(B)=26=13∴ PA=46=23and, PB=26=13 Here, A is estimated to have a possibility of 66.67% and B is estimated to have a possibility of 33.33%. Hence, A has a better estimate, or A has a higher chance of occurring.
If in the roll of a die, event A suggests that a single role will produce a score of 3 or more, and event B suggests that a single role will produce a score of 2 or less, find the better estimate. ⇒ In a die, we know there are six possible scores, that is, {1, 2, 3, 4, 5, 6} For event A, the possible outcomes are {3, 4, 5, 6}, and for event B, the possible outcomes are {1, 2} ∴ P(A)=46=23and, P(B)=26=13∴ PA=46=23and, PB=26=13 Here, A is estimated to have a possibility of 66.67% and B is estimated to have a possibility of 33.33%. Hence, A has a better estimate, or A has a higher chance of occurring.
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 6ECP: In Pennsylvania’s Cash 5 game, a player chooses five different numbers from 1 to 43. If these five...
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If in the roll of a die,
⇒ In a die, we know there are six possible scores, that is, {1, 2, 3, 4, 5, 6}
For event A, the possible outcomes are {3, 4, 5, 6}, and for event B, the possible outcomes are {1, 2}
∴ P(A)=46=23and, P(B)=26=13∴ PA=46=23and, PB=26=13
Here, A is estimated to have a possibility of 66.67% and B is estimated to have a possibility of 33.33%. Hence, A has a better estimate, or A has a higher chance of occurring.
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