If n-23, -36, and s-17, construct a confidence interval at a 90% confidence level. Assume the data cam from a normally distributed population. Give your answers to one decimal place. Can we conclude that the population mean is at least 31.81? O No O Yes Can we conclude that the population mean is no more than 43.29? O No O Yes

Q: If n = 24, ¯xx¯ = 30, and s = 3, construct a confidence interval at a 98% confidence level. Assume…

A: Given: x~N(μ,σ)n=24x¯=30s=3α=0.02

Q: If n = 12, I = 33, and s = 2, construct a confidence interval at a 98% confidence level. Assume the…

A: We have given that  Sample size n= 12 Sample mean = 33 Standard deviation = 2

Q: If n=30, ¯xx¯(x-bar)=43, and s=16, construct a confidence interval at a 98% confidence level. Assume…

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Q: If n = 14, ¯x = 39, and s = 13, construct a confidence interval at a 95% confidence level. Assume…

A: Since the sample size is small and population standard deviation is unknown, t distribution can be…

Q: If n = 15, 43, and s = 9, construct a confidence interval at a 98 % confidence level. Assume the…

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Q: % confidence level. Assume the data came from a normally distributed population. Give your answers…

A: Sample Mean, x̄ = 35.0 sample standard deviation, s = 10.0 Sample Size, n = 24 confidence level, c=…

Q: If n = 16, = 46, and s = 17, construct a confidence interval at a 90% confidence level. Assume the…

A: Given n=16 X-bar=46 S=17

Q: If n = 11, ¯xx¯ = 40, and s = 17, construct a confidence interval at a 98% confidence level. Assume…

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Q: If n=31, ¯xx¯(x-bar)=30, and s=10, construct a confidence interval at a 80% confidence level. Assume…

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Q: If n=14, (x-bar)=37, and s=7, construct a confidence interval at a 98% confidence level. Assume the…

A: Given,n=14x¯=37s=7degrees of freedom(df)=n-1df=14-1=13α=1-0.98=0.02α2=0.01t0.01(13)=2.650     (from…

Q: If n=10, ī(x-bar)=37, and s=19, construct a confidence interval at a 95% confidence level. Assume…

A: From the provided information, Sample size (n) = 10 Sample mean (x̄) = 37 Standard deviation (s) =…

Q: If n=31, (x-bar)=49, and s=3, construct a confidence interval at a 80% confidence level. Assume the…

A: Given, Sample size = 31 Sample mean = 49 Sample standard deviation = 3   Since the population…

Q: If n = 22, ¯xx¯ = 36, and s = 14, construct a confidence interval at a 98% confidence level. Assume…

A: From the provided information, Sample size (n) = 22 Sample mean (x̄) = 36 Standard deviation (s) =…

Q: If n=28, a(x-bar)=36, and s=17, construct a confidence interval at a 98% confidence level. Assume…

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Q: If n = 16, 7 = 43, and s = 17, construct a confidence interval at a 98% confidence level. Assume the…

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Q: If n=13, (x-bar)=43, and s=7, construct a confidence interval at a 99% confidence level. Assume the…

A:

Q: If n=13, (x-bar)=48, and s=12, construct a confidence interval at a 95% confidence level. Assume the…

A: Mean = 48Standard deviation = 12Sample size = 13

Q: If n=12, (x-bar)=33, and s=16, construct a confidence interval at a 80% confidence level. Assume the…

A:

Q: If n = 22, ¯xx¯ = 30, and s = 9, construct a confidence interval at a 98% confidence level. Assume…

A: According to the provided information, n  = 22,  ¯x = 30 s = 9 degrees of freedom = n-1 = 22-1 = 21…

Q: If all other factors are held constant, which confidence level will produce the smallest width for a…

A: Solution Decreasing the confidence level making the confidence interval Smaller.

Q: If n = 17, ¯xx¯ = 33, and s = 6, construct a confidence interval at a 99% confidence level. Assume…

A: We have, If n = 17, x¯ = 33, and s = 6, alpha=1-0.99= 0.01 Therefore  Degrees of freedom= n-1=16…

Q: If n=18, (x-bar)=D43, and s=5, construct a confidence interval at a 98% confidence level. Assume the…

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Q: If n=22, ē(x-bar)=42, and s=19, construct a confidence interval at a 80% confidence level. Assume…

A: Solution: From the given information, n=22, x-bar=42 and s=19.

Q: If n = 28, a = 38, and s = 17, construct a confidence interval at a 99% confidence level. Assume the…

A: As given: n =28 x¯=38 s = 17 It is asked to construct a confidence interval at a 99% confidence…

Q: If n = 16, ¯xx¯ = 32, and s = 10, construct a confidence interval at a 80% confidence level. Assume…

A: We have given that,  Sample mean (x̄) = 32, sample size (n) = 16 and standard deviation (s) = 10…

Q: If n=30, 7(x-bar)=49, and s=14, construct a confidence interval at a 99% confidence level. Assume…

A:

Q: If n-27, (x-bar)=42, and s-4, construct a confidence interval at a 99% confidence level. Assume the…

A: xbar=42  s=4 n=27

Q: If n=23, ¯xx¯(x-bar)=48, and s=2, construct a confidence interval at a 99% confidence level. Assume…

A: Solution-: Given: x¯=48,n=23,s=2,c=0.99 We construct C.I. at a 99% confidence level.

Q: If n=19, ¯xx¯=40, and s=7, construct a confidence interval at a 99% confidence level. Assume the…

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Q: If n=15, ¯xx¯(x-bar)=40, and s=9, construct a confidence interval at a 98% confidence level. Assume…

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Q: If n = 41, ã=30, and s = 6, construct a confidence interval at a 80% confidence level.

A: It is given that Sample size n = 41 Sample mean = 30 Sample SD s = 6 The critical value of t at df =…

Q: If n = 19, ¯xx¯ = 34, and s = 20, construct a confidence interval at a 95% confidence level. Assume…

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Q: If n = 28, ¯xx¯ = 45, and s = 20, construct a confidence interval at a 80% confidence level. Assume…

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Q: If n-31, (x-bar)=40, and s-5, construct a confidence interval at a 98% confidence level. Assume the…

A: Given that  Sample Mean \bar XXˉ = 4040 Sample Standard Deviation (s)(s) = 55 Sample Size…

Q: If n=24, =38, and s=8, construct a confidence interval at a 90% confidence level. Assume the data…

A: Given,n=24x¯=38s=8degrees of freedom(df)=n-1=24-1=23α=1-0.90=0.1α2=0.05t0.05(23)=1.714  (from…

Q: If n=21, (x-bar)=34, and s=8, construct a confidence interval at a 98% confidence level. Assume the…

A: Here, mean is 34 and standard deviation is 8. Sample number is 21. We will use one sample t…

Q: If n = 14, ¯xx¯ = 44, and s = 18, construct a confidence interval at a 95% confidence level. Assume…

A: Given information- Sample size (n) = 14 Mean x̅ = 44 Standard deviation (s) = 18 Significance…

Q: If n = 20, ¯xx¯ = 47, and s = 9, construct a confidence interval at a 90% confidence level. Assume…

A: The degrees of freedom is, df=n-1=20-1=19 The degrees of freedom is 19. Computation of critical…

Q: If n = 23, = 32, and s = 17, construct a confidence interval at a 90% confidence level. Assume the…

A:

Q: If n=13, (x-bar)=43, and s=7, construct a confidence interval at a 99% confidence level. Assume the…

A: The provided sample mean is X¯=43 and the sample standard deviation is s=7. The size of the sample…

Q: If n = 20, ¯xx¯ = 47, and s = 10, construct a confidence interval at a 80% confidence level. Assume…

A:

Q: If n=18, x-bar=47, and s=6, construct a confidence interval at a 98% confidence level. Assume the…

A: In question, Given that n=18, x-bar=47, and s=6. Then we'll construct a confidence interval for…

Q: 15, ¯xx¯(x-bar)=39, and s=11, construct a confidence interval at a 95% confidence level. Assume the…

A: Sample size (n) =15 Sample mean (x¯)=39 Sample standard deviation (s)=11 Confidence level (C)=95%…

Q: If n=19, (x-bar)=41, and s=17, construct a confidence interval at a 99% confidence level. Assume the…

A: The provided information are: Sample size(n)=19Sample mean(x¯)=41Sample standard deviation…

Q: If n=26, (x-bar)=31, and s=14, construct a confidence interval at a 90% confidence level. Assume the…

A: Confidence interval give a range of values for the unknown parameter of the population. The width of…

Q: If n=n= 19, ¯xx¯ = 40, and s=s= 19, construct a confidence interval at a 80% confidence level.…

A: The sample size n is 19.

Q: If n=17, (x-bar)=48, and s=2, construct a confidence interval at a 80% confidence level. Assume the…

A: We have to construct confidence interval for mean of single normal population.

Q: If n-20, 7(x-bar)=31, and s=17, construct a confidence interval at a 95% confidence level. Assume…

A: Given that n =20 ,s =17 ,x bar =31 ,alpha =0.05

Q: If n=16, 7(x-bar)=38, and s=12, construct a confidence interval at a 99% confidence level. Assume…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: If n=22, 7(x-bar)=34, and s=17, construct a confidence interval at a 99% confidence level. Assume…

A: According to the given information, we have Sample size, n = 22 Sample mean = 34 Sample standard…