If the cell is a standard one, write the spontaneous overall reaction and calculate the voltage that is generated. Ni2+ + Cd ---> Ni + Cd2+ and +0.153 V Ni + Cd2+ Ni2+ + Cd and +0.153 V Ni2+ + Cd ---> Ni + Cd2+ and -0.153 V Ni + Cd2+ --> Ni2+ + Cd and -0.073 V

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Chapter18: Electrochemistry
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Problem 115AE: The saturated calomel electrode. abbreviated SCE. is often used as a reference electrode in making...
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One-half of an electrochemical cell consists of a pure nickel electrode in a solution of
Ni2+ ions; the other half is a cadmium electrode immersed in a Cd2+ solution. Use
the following standard emf series Table (if required).
Standard Electrode
Electrode Reaction
Potential, V" (V)
Au³+ + 3e → Au
+1.420
O2 + 4H+ + 4e
Pr2+ + 2e
2H2O
+1.229
Pt
-+1.2
Ag+ + e
Fe+ + e
→ Ag
Fe2+
+0.800
+0.771
Increasingly inert
(cathodic)
O2 + 2H,O + 4e
Cu²+ + 2e
4(OH)
+0.401
Cu
+0.340
2H* + 2e
Pb2+ + 2e
H2
0.000
Pb
-0.126
Sn2+ + 2e
Sn
-0.136
Ni2+ + 2e
Ni
-0.250
Co2+ + 2e
Cd²+ + 2e
Fe+ + 2e
Co
-0.277
Cd
-0.403
Fe
-0.440
Cr+ + 3e
Cr
-0.744
Increasingly active
(anodic)
Zn2+ + 2e¯
Zn
-0.763
AF+ + 3e
Al
-1.662
Mg²+ + 2e
Mg
-2.363
Na+ + e –→ Na
-2.714
K* + e -→ K
-2.924
If the cell is a standard one, write the spontaneous overall reaction and calculate the
voltage that is generated.
Ni2+ + Cd ---> Ni + Cd2+ and +0.153 V
Ni + Cd2+ ---> Ni2+ + Cd and +0.153 V
Ni2+ + Cd ---> Ni + Cd2+ and -0.153 V
Ni + Cd2+
Ni2+ + Cd and -0.073 V
--->
Transcribed Image Text:One-half of an electrochemical cell consists of a pure nickel electrode in a solution of Ni2+ ions; the other half is a cadmium electrode immersed in a Cd2+ solution. Use the following standard emf series Table (if required). Standard Electrode Electrode Reaction Potential, V" (V) Au³+ + 3e → Au +1.420 O2 + 4H+ + 4e Pr2+ + 2e 2H2O +1.229 Pt -+1.2 Ag+ + e Fe+ + e → Ag Fe2+ +0.800 +0.771 Increasingly inert (cathodic) O2 + 2H,O + 4e Cu²+ + 2e 4(OH) +0.401 Cu +0.340 2H* + 2e Pb2+ + 2e H2 0.000 Pb -0.126 Sn2+ + 2e Sn -0.136 Ni2+ + 2e Ni -0.250 Co2+ + 2e Cd²+ + 2e Fe+ + 2e Co -0.277 Cd -0.403 Fe -0.440 Cr+ + 3e Cr -0.744 Increasingly active (anodic) Zn2+ + 2e¯ Zn -0.763 AF+ + 3e Al -1.662 Mg²+ + 2e Mg -2.363 Na+ + e –→ Na -2.714 K* + e -→ K -2.924 If the cell is a standard one, write the spontaneous overall reaction and calculate the voltage that is generated. Ni2+ + Cd ---> Ni + Cd2+ and +0.153 V Ni + Cd2+ ---> Ni2+ + Cd and +0.153 V Ni2+ + Cd ---> Ni + Cd2+ and -0.153 V Ni + Cd2+ Ni2+ + Cd and -0.073 V --->
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