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- 2. Make a sketch of two sinewaves as follows. Sinewave A is the reference and sinewave B lags A by 90°. Both have equal amplitudes.Assum rms for the phase currentWhen a resistor is connected across the terminals of an ac generator (117 V) that has a fixed frequency, there is a current of 0.332 A in the resistor. When an inductor is connected across the terminals of the same generator, there is a current of 0.365 A in the inductor. When both the resistor and the inductor are connected in series between the terminals of this generator, what is (a) the impedance of the series combination and (b) the phase angle between the current and the voltage of the generator? Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise. (a) Number (b) Number Buda i Vrms R Irms.R Circuit 1 Units Units Vrms. Irms, L Circuit 2 > L Vrms R www Circuit 3
- x (23) WhatsApp x4 Meet-hpd-sdbt-gho web.wl jil O Google bilp YouTube Gmal M Cou Harmonics generated due to the presence of switching power electronic devices are called Answer: An induction machine IS supplied t prase input yoltage of 22 and input current 204-14. The per phaseA single-phase AC voltage controller has a resistive load R = 10 Ohm, and the RMS input voltage is Vs = 230 V, 60 Hz. The delay angle is 120 degree. Then the RMS output voltage is: Select one: O a. 101 V O b. 39 V O c. None of the above O d. 143 V O e. 215 VStandard alternating e.m.f. achieves its positive maximum value at 90°. Select one: True False
- what will be the power factor, if the inductive reactance is equal to the capacitive reactance of 20 Q and the resistance is 20 Q. O a. Unity O b. Zero O c. Leading O d. Lagging"If lab is equal to 595.8252306 and lb is 344296, the phase sequence is:" O POSITIVE O NEGATIVEQUESTION 3 An inductor, a capacitor, and a resistor are connected in parallel with a function generator. The inductor draws 100mA RMS, the capacitor draws 150mA RMS, and the resistor draws 200mA RMS. Find the magnitude of the total current. O 450mA RMS O 544mA RMS O 352mA RMS O 206mA RMS
- A 220 Ω resistor is in series with an 80 mH inductor. The AC source is 48 at 1 kHz. The power factor is ________. Hint: Draw the circuit and get Vs and IsA single-phase AC voltage controller has a resistive load R = 10 Ohm, and the RMS input voltage is Vs = 230 V, 60 Hz. The delay angle is 120 degree. Then power factor of the circuit is: Select one: O a. 1 O b. 0.75 O c. 0.44 O d. None of the above O e. 0.9in V1 R2 100k SINE(0 10 100) R1 100k D1 D V2 0 out D D2 V3 0 DC offset[V]: 0 Amplitude[V]: 10 Freq[Hz]: 100 T delay[s]: Theta[1/s]: Phi[deg]: Ncycles: anter 2019-2220 Figure 3-5 Clipper Circuit for LTSPICE Simulation C4. To specify the type of simulation, select "Simulate>>Edit Simulation Cmd" from the menu. Choose "Transient" and enter 30m for Stop time, 0 for Time to start saving data, and 1m for Maximum Timestep. Click OK. C5. Click Run to start the analysis. C6. Place two voltage probes (voltage probes appear when placed on a wire during simulation), one at the input side (at the top of V1) and another at the output side (at the top of D2) of the circuit. What difference do you observe between the input and the output waveforms?