If the viscosity of blood is 2.1 x 10^-3 pa.s, and capillary of 100 um radius has a length of 4cm , then the blood flow resistance a cross this capillary be *
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- Water supplied to a house by a water main has a pressure of 3.00 X 105 N/m2 early on a summer day when neighborhood use is low. This pressure produces a flow of 20.0 L/min through a garden hose. Later in the day, pressure at the exit of the water main and entrance to the house drops, and a flow of only 8.00 L/min is obtained through the same hose. (a) What pressure is now being supplied to the house, assuming resistance is constant? (b) By what factor did the flow rate in the water main increase in order to cause this decrease in delivered pressure? The pressure at the entrance of the water main is 5.00 X 105 N/m2, and the original flow rate was 200 L/min. (c) How many more users are there, assuming each would consume 20.0 L/min in the morning?What is the conductance of a 1.0 mm diameter, 10 cm-long blood vessel filled with blood? Express your answer with the appropriate units. FYI: It will not accept 4.91 x 10^(-6) ohms.In one form of plethysmograph (a device for measuring volume), a rubber capillary tube with an inside diameter of 1.30 mm is filled with mercury at 20°C. The resistance of the mercury is measured with the aid of electrodes sealed into the ends of the tube. If 100.00 cm of the tube is wound in a spiral around a patient's upper arm, the blood flow during a heartbeat causes the arm to expand, stretching the tube to a length of 100.20 cm. From this observation, and assuming cylindrical symmetry, you can find the change in volume of the arm, which gives an indication of blood flow. Take ?Hg = 9.4 ✕ 10−7 Ω · m. (a) Calculate the resistance of the mercury. (b) Calculate the fractional change in resistance during the heartbeat. Hint: Because the cylindrical volume is constant, V = Ai Li = Af Lf and Af = Ai(Li/Lf).
- In one form of plethysmograph (a device for measuring volume), a rubber capillary tube with an inside diameter of 1.00 mm is filled with mercury at 20°C. The resistance of the mercury is measured with the aid of electrodes sealed into the ends of the tube. If 100.00 cm of the tube is wound in a spiral around a patient’s upper arm, the blood flow during a heartbeat causes the arm to expand, stretching the tube to a length of 100.04 cm. From this observation, and assuming cylindrical symmetry, you can find the change in volume of the arm, which gives an indication of blood flow. (a) Calculate the resistance of the mercury. (b) Calculate the fractional change in resistance during the heartbeat. Take ρHg = 9.4 × 10−7 Ω m. Hint: Because the cylindrical volume is constant, V = AiLi = and Af = Ai(Li/Lf )Water supplied to a house by a water main has a pressure of 3.00105 N/m2 early on a summer day when neighborhood use is low. This pressure produces a flow of 20.0 L/min through a garden hose. Later in the day, pressure at the exit of the water main and entrance to the house drops, and a flow of only 8.00 L/min is obtained through the same hose. (a) What pressure is now being supplied to the house, assuming resistance is constant? (b) By what factor did the flow rate in the water main increase in order to cause this decrease in delivered pressure? The pressure at the entrance of the water main is 5.00105 N/m2, and the original flow rate was 200 L/min. (c) How many more users are there, assuming each would consume 20.0 L/min in the morning?Integrated Concepts (a) Referring to Figure 20.34, find the time systolic pressure lags behind the middle of the QRS complex, (b) Discuss the reasons for the lime lag. Figure 20.34 A lead II ECG with corresponding arterial blood pressure. The QRS complex is created by the depolarization and contraction of the ventricles and is followed shortly by the maximum or systolic blood pressure. See text for further description.
- A ball of a mass of 2kg is dropped from rest in a viscous fluid, the resistance of which is 0.001v Newton where v is the instantaneous velocity is m/s. What is the velocity and distance traveled by the ball after 44 seconds?If the blood viscosity is 2.7x10-3 Pa.s, length of the blood vessel is 0.2 m , tubular resistance of the blood vessel is 325 GPa-s/m3, what is the radius of the blood vessel, in mm?00-gauge copper wire has a diameter of 9.266 mm.Calculate the power loss in a kilometer of such wire when it carries 1.00×102 A .
- The femoral artery is the large artery that carries blood to the leg. A person’s femoral artery has an inner diameter of 1.0 cm. What is the resistance of a 20-cm-long column of blood in this artery?A fluid-filled catheter is 100 cm long and has a diameter of 1 mm. What is the resistance to the blood flow when the viscosity of blood is 0.0027 Newton-seconds (N-s)/m2. Calculate resistance in GPa-s/m3.Water supplied to a house by a water main has apressure of 3.00×105 N/m2 early on a summer day whenneighborhood use is low. This pressure produces a flow of20.0 L/min through a garden hose. Later in the day, pressureat the exit of the water main and entrance to the house drops,and a flow of only 8.00 L/min is obtained through the samehose. (a) What pressure is now being supplied to the house,assuming resistance is constant? (b) By what factor did theflow rate in the water main increase in order to cause thisdecrease in delivered pressure? The pressure at the entranceof the water main is 5.00×105 N/m2 , and the original flowrate was 200 L/min. (c) How many more users are there,assuming each would consume 20.0 L/min in the morning?