Please need help with 24 25 26 please Here is JMP output comparing top of the line bats to lower priced bats. Thedistance in feet that a ball was hit is measured.-Oneway Analysis of Distance Hit (ft) By Type of Bat7936055lower priceType of Bat4 Oneway Anova4 Summary of FitRsquareAdj RsquareRoot Mean Square ErrorMean of ResponseObservations (or Sum Wgts)4 Pooled t Testtop of the line-lower priceAssuming equal variancesDifferenceStd Err DifUpper CL DifLower Dif11top of the line0.2507370.2091114.49162860.605204.93000 t Ratio2.00872 DF9.15016 Prob> t070984 Prob > t22332.454303180.0245*0.0123*Normal Quantle900.95the line If this was 2 sample independent data, what assumption(s) would we need tocheck?25normally distributed dataequal variancesall np. > 5multinomial experimentall E > 5What is the value of our test statistic? Round to 2 decimal places.Type your answer..26What is the critical value for the rejection region if this was a less than alternativehypothesis at the 1% significance level? Round to 3 decimal places.Type your answer.....

Hypothesis is an assumption that is being tested.

Answered: If this was 2 sample independent data,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. Full data set Carpeted Uncarpeted 7.5 14.9 9.4 5.1 10.6 4.2 9.2 12.7 9.9 13.3 9.3 4.2 6.9 11.1 7.5 12.5 Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the α=0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. A. H0: μ1=μ2 H1: μ1>μ2 This is the correct answer. B. H0: μ1<μ2 H1: μ1>μ2 C. H0: μ1=μ2 H1: μ1≠μ2 D. H0: μ1=μ2 H1: μ1<μ2 Your answer is not correct. Determine the P-value for this hypothesis test. P-value=nothing…
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The article “Dynamics of Insulin Action in Hypertension: Assessment from Minimal ModelInterpretation of Intravenous Glucose Tolerance Test Data” (R. Burattini, M. Morettini, etal., Med Biol Eng Comput, 2011:831–841) compared levels of an insulin sensitivity index SIin patients with high blood pressure and patients with normal blood pressure. Ten patientswith high blood pressure had a mean value of 3.4 with a standard deviation of 0.6, and eightpatients with normal blood pressure had a mean value of 7.9 with a standard deviation of0.6. Units are 10−5 · min−1 · pmol−1. Find a 98% confidence interval for the difference inmean levels between those with high blood pressure and those with normal blood pressure.
Lactation promotes a temporary loss of bone mass to provide adequate amounts of calcium for milk production. The paper “Bone Mass Is Recovered from Lactation to Postweaning in Adolescent Mothers with Low Calcium Intakes” (Amer. J. of Clinical Nutr., 2004:1322-1326) gave the following data on total body bone mineral content (TBBMC) (g) for a sample both during lactation (L) and in postweaning period (P). (Let = true mean difference in TBBMC, postweaning minus lactation.) Subject 1 2 3 4 5 6 7 8 9 10 L 1928 2549 2825 1924 1628 2175 2114 2621 1843 2541 P 2126 2885 2895 1942 1750 2184 2164 2626 2006 2627 Does the data suggest that true average total body bone mineral content during postweaning exceeds that during lactation by more than 25 g? State and test the appropriate hypotheses using a significance level of .05. [Note: The appropriate normal probability plot shows some curvature but not enough to…
Lactation promotes a temporary loss of bone mass to provide adequate amounts of calcium for milk production. The paper “Bone Mass Is Recovered from Lactation to Postweaning in Adolescent Mothers with Low Calcium Intakes” (Amer. J. of Clinical Nutr., 2004: 1322–1326) gave the following data on total body bone mineral content (TBBMC) (g) for a sample both during lactation (L) and in the postweaning period (P). SubjectL 1928 2549 2825 1924 1628 2175 2114 2621 1843 2541P 2126 2885 2895 1942 1750 2184 2164 2626 2006 2627 Does the data suggest that true average total body bone mineral content during postweaning exceeds that during lactation by more than 25 g? State and test the appropriate hypotheses using a significance level of .05.
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An experiment was conducted to test whether students’ performance (above or below average) is independent of stress level as a result of pressure on time table for the term in Hwanhwan Senior High School. The table below gives a 3 × 2 contingency table of the sample. Above Average Average Below Average Total Stressed 135 250 285 670 Not Stressed 150 157 107 414 Total 285 407 392 1084 With the help of chi-square test statistics, determine whether students' performance for the selected term in the school is independent of their stressed level experienced from the time table at α = 0.05

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