5alvy#3. If two masses 7 kg and 17 kg have velocities < 6, -10> and < -10, 3> respectively, find the final=7(x)velocity of the 17 kg object.7 (6) + 17 (-10)"+17(4)-128 = 7 (x) +17√-8.518-0.41221-26 384 = 49x² + 2891-8.51.8 -0.412 x ²):½/²2 ( 7 ) ( x ²) + 2/₂2 (17) (4²= 3.5 x² + 8.54²a) Find the final velocity of the 5 kg object if the collision is elastic.½/22 (7) (6) ² + ½/22 (17) (-10)2-724- 16384 = 49x3240-13922.298=X = 13.441(13.491, 3.125>√-8518-10-412x2Write your answer as a speed and direction: |||| =(m/s) 0 =(degrees)(9) (-10) + ½/₂2 (17) (3) = 1/2 (7) (x ² ) + ½/22 (17) (4²) 1 (-10) +17 (3) = 7(2qd-3.5x = 8.Sy1-118-0.482x².147 € 7x- #176√-1.1361 = 44x + 289(-1b) If the collision is perfectly inelastic and the objects stick together, what is the final kinetic energyof the compound object?3(1=49x² + 323.10-68 4.102 = -1₂0.068,x = 3.125

Name: 5alvy#3. If two masses 7 kg and 17 kg have velocities and <
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Description: 5alvy#3. If two masses 7 kg and 17 kg have velocities and respectively, find the final=7(x)velocity of the 17 kg object.7 (6) + 17 (-10)"+17(4)-128 = 7 (x) +17√-8.518-0.41221-26 384 = 49x² + 2891-8.51.8 -0.412 x ²):½/²2 ( 7 ) ( x

Given that:m1=7 kgu1→=<6,-10> =(6i^-10j^) m/sm2=17 kgu2→=<-10,3>=(-10i^+3j^) m/s

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If two masses 7 kg and 17 kg have velocities < 6, -10> and < -10, 3> respectively, find the final city of the 17 kg object. = 7(x) +17(4). 7 (6) + 17 (-10) -128 = 7 (x) + 177-8.518-0.412 1-26384 = 49x² + 2891-8.51.8 -0.412 x ²2 =) Find the final velocity of the 5 kg object if the collision is elastic. ½/22 (7) (6) ² + ½/2/2 (17) (-10) = //2² (7) (x ² ) + ½/₂2 (17) (4² = 3-√√ x² + 8.54²2 -724 V-8518-10 412 x 2 Write your answer as a speed and direction: |||| = ½ (9) (10) - 16354 = 49x² = 24 -13922.298= X = 13.741 (13.491, 3.125- (m/s) 0 = + ½/22 (17) (3) = ²/₂2 (7) (x²) + ½ 2₂2 ( 17 ) (Y²) -9.5 = 3.5 x ² + {₂.g2 --3.5x = 8.Sy ) If the collision is perfectly inelastic and the objects stick together, what is the final of the compound object? (degrees) 1. (-10) +17(3) = 76 197 = 7x- #17 (√+ 3-1-118-0.482 x ² ~ 351 = 49x² + 289(- kinetic energy 3(1=49x²² 323.1 +68 4.102=22-11720.068 x

If two masses 7 kg and 17 kg have velocities < 6, -10> and < -10, 3> respectively, find the final city of the 17 kg object. = 7(x) +17(4). 7 (6) + 17 (-10) -128 = 7 (x) + 177-8.518-0.412 1-26384 = 49x² + 2891-8.51.8 -0.412 x ²2 =) Find the final velocity of the 5 kg object if the collision is elastic. ½/22 (7) (6) ² + ½/2/2 (17) (-10) = //2² (7) (x ² ) + ½/₂2 (17) (4² = 3-√√ x² + 8.54²2 -724 V-8518-10 412 x 2 Write your answer as a speed and direction: |||| = ½ (9) (10) - 16354 = 49x² = 24 -13922.298= X = 13.741 (13.491, 3.125- (m/s) 0 = + ½/22 (17) (3) = ²/₂2 (7) (x²) + ½ 2₂2 ( 17 ) (Y²) -9.5 = 3.5 x ² + {₂.g2 --3.5x = 8.Sy ) If the collision is perfectly inelastic and the objects stick together, what is the final of the compound object? (degrees) 1. (-10) +17(3) = 76 197 = 7x- #17 (√+ 3-1-118-0.482 x ² ~ 351 = 49x² + 289(- kinetic energy 3(1=49x²² 323.1 +68 4.102=22-11720.068 x

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter8: Linear Momentum And Collisions

Section: Chapter Questions

Problem 24PE: Suppose a clay model of a koala bear has a mass of 0.200 kg and slides on ice at a speed of 0.750...

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