(ii) Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to calculate the electron affinity of chlorine: Ca(s) Ca(g) AHat = +190 kJ/mol Ca(g) Ca, (g) + 2e AHE = +1730 kJ/mol C2(g) 2CI(g) AHat = +121 kJ/mol Ca2*(g) + 2CI(g) CaCl2(s) AHLE = -2184 kJ/mol Ca(s) + Cl2(g) – CaCl2(s) AHĘ = -795 kJ/mol

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter8: The Periodic Table: Structure And Trends
Section: Chapter Questions
Problem 8.102QE
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(ii) Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to
calculate the electron affinity of chlorine:
Ca(s)
→ Ca(g)
AHat = +190 kJ/mol
Ca(g)
> Caz*(g) + 2e¨ AH¡ɛ = +1730 kJ/mol
Cl2{g)
2C1(g)
AHat = +121 kJ/mol
Caz (g) + 2Cl(g)
> CaCl2(s)
AHLE = -2184 kJ/mol
Ca(s) + Cl2(g) –> CaCl2(s) AH; = -795 kJ/mol
Transcribed Image Text:(ii) Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to calculate the electron affinity of chlorine: Ca(s) → Ca(g) AHat = +190 kJ/mol Ca(g) > Caz*(g) + 2e¨ AH¡ɛ = +1730 kJ/mol Cl2{g) 2C1(g) AHat = +121 kJ/mol Caz (g) + 2Cl(g) > CaCl2(s) AHLE = -2184 kJ/mol Ca(s) + Cl2(g) –> CaCl2(s) AH; = -795 kJ/mol
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