Implement the following pseudo-code in MIPS. You need to define the vectors (sx and sy) and other variables (N) in the data section (under .data). All vectors are of N, which are initialized using a separate call.
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![Implement the following pseudo-code in MIPS. You need to define the vectors (sx and sy) and
other variables (N) in the data section (under .data). All vectors are of N, which are initialized
using a separate call.
#define N 10
int s[N], sy[N];
init()
{
for (int i=0; i<N; i++)
{
sx[i]
sy[i]
}
i+1;
i+2;
axpy(int sa)
{
call init();
for (int i=0; i<N; i++)
{
sy[i] = sy[i] + sa*sx[i];
}
main()
{
ахру (5);
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa3570164-4b18-440c-8c4b-9050a2bbc405%2F0243e99d-9a65-4f1a-a4ba-bf81c7f21251%2Fk3vzek_processed.png&w=3840&q=75)
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- Implement the following function, without using any data structure or #include <bits/stdc++.h> /* Given two vectors of chars, check if the two vectors are permutations of each other, i.e., they contains same values, in same or different order.e.g., V1=[‘a’,’b’,’a’] and V2=[‘b’,’a’,’a’] stores same multi-set of data points: i.e., both contains two ‘a’, and one ‘b’. e.g., V3=[‘a’,’c’,’t’,’a’] and V4=[‘a’,’c’,’t’] are not same multi-set. V3 contains two ‘a’s, while V4 has only one ‘a’. Note: when considering multiset, the number of occurrences matters. @param list1, list2: two vectors of chars @pre: list1, list2 have been initialized @post: return true if list1 and list2 stores same values (in same or different order); return false, if not. */ bool SameMultiSet (vector<char> list1, vector<char> list2) THIS IS NOT THE CORRECT SOLUTION / include headers #include <bits/stdc++.h> // deinfe the namespace using namespace std; // function fo rchecking same bool…A set of integers 0..MAX may be implemented using an array of boolean values. This particular implementation is called a bit-vector implementation of a Set. Since C doesn’t have the Boolean data type, then substitute TRUE with 1 and FALSE with 0, or define 1 and 0 as TRUE and FALSE, respectively.For example, if the integer 3 is an element of the set, then the array element indexed by 3 is TRUE. On the other hand, if 3 is not an element, then the array element indexed by 3 is FALSE. For example, if the integer 3 is an element of the set, then the array element indexed by 3 is TRUE. On the other hand, if 3 is not an element, then the array element indexed by 3 is FALSE.For example: if s = {3,4,6,8}, the array looks like this: Implement a programmer-defined data type called BitSet to represent a set as follows:typedef int BitSet[MAX];Implement the following functions:void initialize(BitSet s); - set all array elements to FALSEvoid add(int elem,BitSet s);- set the item indexed by elem to…The vector x ∈ R N has L different entries. For example, L = 4 for x = [3,4,4,5,3,1,5,3]T . One can express x as x = S u, where u ∈ R L satisfies (u)i < (u)j if i < j and S is a matrix that contains only zeros and ones. Write the function repeated_entries, which takes x as input and returns S and u.
- implement the Viterbi algorithm in Python. Your task is to write codefor the following prototype:def Viterbi(A,B,Pi,O) Returning Viterbi score and best path2. Calculate the Viterbi score and the Best path of the first two vectorsdescribed in part 1 of this assignment by hand. Show your work.3. Create an observation vector of at least 7 elements.4. Use the observation vectors and results calculated in 2. and 3. above totest your implementation of the Viterbi algorithmimplement QuickSort of ints that sorts the numbers in the non-decreasing order. Implement the rearrange function using QuickSort ( such that the pivot is set on the extreme left and the rearrangement is carried on on two pointers) using the O(n) time algorithmThe function gets as input an array, and index of the pivot.The function rearranges the array, and returns the index of the pivot after the rearrangement. int rearrange(int* A, int n, int pivot_index); Implement the QuickSort algorithm. - For n<=2 the algorithm just sorts the (small) array (smaller number first). - For n>=3 the algorithm uses the rearrange function with the pivot chosen to be the median of A[0], A[n/2], A[n-1]. void quick_sort(int* A, int n);) Consider the following C code snippet. void swap(int *xp, int *yp) { int temp = *xp; *xp = *yp; *yp = temp; } int findMinimum(int arr[], int N) { // variable to store the index of minimum element int min_idx = 0; int min_E = arr[min_idx]; // Traverse the given array for (int i = 1; i < N; i++) { // If current element is smaller than min_idx then update it if (arr[i] < min_E) { min_idx = i; min_E = arr[min_idx]; } } return min_idx; } /* Function to sort an array using selection sort*/ void selectionSort(int arr[], int n) { int i, min_idx; // One by one move boundary of unsorted subarray for (i = 0; i < n-1; i++) { // Find the minimum element in unsorted array min_idx = findMinimum(&arr[i], n-i); // Swap the found minimum element with the first element if(min_idx != 0) swap(&arr[min_idx+i], &arr[i]); } }…
- Write pseudocode for a function Det-Quicksort(A, p, r) that receives array A[1..n], and indices p and r. The function should sort the subarray A[p..r] recursively (meaning you should call itself). You can also use a function LinearSearch(A, p, r, v) that searches subarray A[p..r] for an element of value v and return its index (in case it exists) in O(r − p) time. (Just to give you something to compare to, the solution has 8 lines.)Find the number of super values in vector<int>v where an array element is super if it is greater than all elements to its right. For ex in {4,27,1,20,17, 5} has 4 super values 27, 20,17,5 so its output should be 4. Code in C++Implement a range function for a dynamic array which returns a new dynamic array that is a subset of the original. input parameters: array - (the array and any related parameters) start - index of the first elementend - index of the last elementInterval - An integer number specifying the incrementation of index This function returns a new dynamic array containing the elements from the start thru the end indices of the original array.All array indexing must be done using pointer arithmetic. For example, given the array: 49 96 99 47 76 29 22 16 30 22 If the start and end positions were 5 and 9 with step 2, return a new dynamic array: 29 16 22 Please use following main to test your function. int main(){int *p = new int[10]{49,96,99,47,76,29,22,16,30,22}; int *q = range(p,10,5,9,2);for(int i=0;i<3;i++) cout<<q[i]<<" "; // print 29 16 22 cout<<endl;delete [] q;q = range(p,10,1,8,3); for(int i=0;i<3;i++)cout<<q[i]<<" "; // print 96 76 16 cout<<endl;…
- Given two arrays A and B of equal size N, the task is to find a vector containing only those elements which belong to exactly one array - either A or B - but not both. That is, if some element x appears in both A and B it should not be included in the output vector. Complete the implementation of "getVector(vector<ll>A, vector<ll>B, int N)" function. Example: Input: 1 3 5 7 1 3 2 4 6 7 8 Output: 3 5 1 3 2 4 6 8 The driver codes are attached in the images below. DO NOT CHANGE THE PROVIDED DRIVER CODES AT ALL, LEAVE THEM EXACTLY THE SAME. ONLY ADD CODE TO THE "getVector(vector<ll>A, vector<ll>B, int N)" FUNCTIONWrite a code in "C"that can swap all the values of its first row with its last row in a [n×m] matrix After swapping, add all the values of the last column.Write a program using c# to do the following: Initialize an array A with 10 elements. Initialize an array B with 7 elements. Divide each element of array A with each element of array B that is a[0]/b[0] , a[1]/b[1] etc. Implement the same to handle divide by zero error and index out of bound error.