In a balanced three-phase Y-Y system, the source is an abc sequence of voltages and Vab = 476∠3° Vrms. The line impedance per phase is 0.7 + j1.3Ω , while the per-phase impedance of the load is 13 + j13Ω . Calculate the magnitude of the phase-c line current (in Arms).

In a balanced three-phase Y-Y system, the source is an abc sequence of voltages and Vab = 476∠3° Vrms. The line impedance per phase is 0.7 + j1.3Ω , while the per-phase impedance of the load is 13 + j13Ω . Calculate the magnitude of the phase-c line current (in Arms).

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.24MCQ: It is stated that (i) balanced three-phase circuits can be solved in per unit on a per-phase basis...

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Concept explainers

Single Phase AC Circuit

Alternating Current (AC) is a type of electric power in which the electric current changes, both in magnitude and direction, at regular intervals. This AC Circuits can deliver power in either a Single Phase system or a Three Phase system.

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17)

In a balanced three-phase Y-Y system, the source is an abc sequence of voltages and Vab = 476∠3° V_rms. The line impedance per phase is 0.7 + j1.3Ω , while the per-phase impedance of the load is 13 + j13Ω . Calculate the magnitude of the phase-c line current (in A_rms).

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