In a certain school district, it was observed that 35% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 160 out of 387 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the a = 0.05 level of significance.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 30PPS
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In a certain school district, it was observed that 35% of the students in the element schools were
classified as only children (no siblings). However, in the special program for talented and gifted
children, 160 out of 387 students are only children. The school district administrators want to know
if the proportion of only children in the special program is significantly different from the proportion
for the school district. Test at the a = 0.05 level of significance.
What is the hypothesized population proportion for this test?
p =
(Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.)
Based on the statement of this problem, how many tails would this hypothesis test have?
O one-tailed test
O two-tailed test
Choose the correct pair of hypotheses for this situation:
(A)
(B)
(C)
Но: р— 0.35
Ha:p < 0.35
Но: р — 0.35
H:p+ 0.35
Но:р— 0.35
Haip> 0.35
(D)
(E)
(F)
Ho:p= 0.413 Ho:p 0.413 Ho:p 0.413
Ha:p< 0.413 H.:p 0.413 Ha p> 0.413
(A)
(E) (F)
Co
30
Transcribed Image Text:In a certain school district, it was observed that 35% of the students in the element schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 160 out of 387 students are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the a = 0.05 level of significance. What is the hypothesized population proportion for this test? p = (Report answer as a decimal accurate to 2 decimal places. Do not report using the percent symbol.) Based on the statement of this problem, how many tails would this hypothesis test have? O one-tailed test O two-tailed test Choose the correct pair of hypotheses for this situation: (A) (B) (C) Но: р— 0.35 Ha:p < 0.35 Но: р — 0.35 H:p+ 0.35 Но:р— 0.35 Haip> 0.35 (D) (E) (F) Ho:p= 0.413 Ho:p 0.413 Ho:p 0.413 Ha:p< 0.413 H.:p 0.413 Ha p> 0.413 (A) (E) (F) Co 30
Using the normal approximation for the binomial distribution (without the continuity correction),
what is the test statistic for this sample based on the sample proportion?
(Report answer as a decimal accurate to 3 decimal places.)
You are now ready to calculate the P-value for this sample.
P-value =
(Report answer as a decimal accurate to 4 decimal places.)
This P-value (and test statistic) leads to a decision to..
O reject the null
O accept the null
O fail to reject the null
O reject the alternative
As such, the final conclusion is that...
O There is sufficient evidence to warrant rejection of the assertion that there is a different
proportion of only children in the G&T program.
O There is not sufficient evidence to warrant rejection of the assertion that there is a different
proportion of only children in the G&T program.
O The sample data support the assertion that there is a different proportion of only children in
the G&T program.
O There is not sufficient sample evidence to support the assertion that there is a different
proportion of only children in the G&T program.
Transcribed Image Text:Using the normal approximation for the binomial distribution (without the continuity correction), what is the test statistic for this sample based on the sample proportion? (Report answer as a decimal accurate to 3 decimal places.) You are now ready to calculate the P-value for this sample. P-value = (Report answer as a decimal accurate to 4 decimal places.) This P-value (and test statistic) leads to a decision to.. O reject the null O accept the null O fail to reject the null O reject the alternative As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program. O There is not sufficient evidence to warrant rejection of the assertion that there is a different proportion of only children in the G&T program. O The sample data support the assertion that there is a different proportion of only children in the G&T program. O There is not sufficient sample evidence to support the assertion that there is a different proportion of only children in the G&T program.
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