In a circle, the perpendicular bisector of a chord contains the center of the circle. Given: OX with L the bisector of WY. Prove: L contains the center of OX. Statements 1.Connect points X and W and X and Y to form ▼ 2. 3.X is on the bisector of 4.X is on ▼ 5 L contains the center of OX (…) W X Y 1. Construction 2. All radii of a circle are 3. Converse of the Bisector Theorem 4. Substitution 5. Reasons
In a circle, the perpendicular bisector of a chord contains the center of the circle. Given: OX with L the bisector of WY. Prove: L contains the center of OX. Statements 1.Connect points X and W and X and Y to form ▼ 2. 3.X is on the bisector of 4.X is on ▼ 5 L contains the center of OX (…) W X Y 1. Construction 2. All radii of a circle are 3. Converse of the Bisector Theorem 4. Substitution 5. Reasons
Elementary Geometry for College Students
6th Edition
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Daniel C. Alexander, Geralyn M. Koeberlein
Chapter10: Analytic Geometry
Section10.4: Analytic Proofs
Problem 28E
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