In a clinical trial of a drug intended to help people stop smoking, 126 subjects were treated with the drug for 13 weeks, and 19 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.17 as an alternative value of p, the power of the test is 0.95. Interpret this value of the power of the test.
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- A well-known brokerage firm executive claimed that at least 90% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 800 people, 88% of them said they are confident of meeting their goals. What practical conclusion can we make about the claim? What would be our formal conclusion if we used a 0.01 significance level?In a studyy of smokers who tried to quit smoking with nicotine patch therapy, 39 were smoking one year after the treatment, and 32 were not smoking one year after the treatment. We want to use a 0.05 significance level to test the claim that among smokers who try to quit with nicotine patch therapy, the majority are smoking a year after the treatment. a) What is the null hypothesis? b) What is the alternative hypothesis? c) What is the value of the standard score for the sample proportion? d) What is the P-value? e) Describe a type I error for this test. f) Describe a type II error for this test.In a survey, 716 out of 1132 randomly selected adults in the United States said that they use cell phones while driving. a) Use a 0.02 significance level when testing the claim that the proportion of adults who use cell phones while driving is different than 70%. b) What does the conclusion mean?
- In the previous year, 40% of women over the age of fifty had regularly scheduled mammograms. Following last year's test, a campaign was initiated to encourage women to be tested regularly. This year, a cancer research group surveys a random sample of 450 women, and 195 respond affirmatively. With a 5% significance level, test to see if the campaign was effective. What is the null hypothesis? options: H0: μ ≤ 0.4 H0: μ ≥ 0.4 H0: p ≠ 0.4 H0: p ≥ 0.4 H0: p ≤ 0.4 H0: μ ≠ 0.4 None of these.In a clinical trial of a drug intended to help people stop smoking, 131 subjects were treated with the drug for 13 weeks, and 13 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value of p, the power of the test is 0.96. Interpret this value of the power of the test.A national publishing house claims that 45% of all weekly magazine readers in South Africa read their publication. Test this claim at the 5% significance level, if a survey found that 205 out of a random sample of 500 magazine readers said that they read the relevant publication.
- In a clinical trial of a drug intended to help people stop smoking, 129 subjects were treated with the drug for 11 weeks, and 12 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominalpain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.18 as an alternative value of p, the power of the test is 0.96 Interpret this value of the power of the test.A Gallup poll to survey the top concerns of Americans was conducted. Suppose that 566 women and 465 men were independently and randomly selected and that 322 women and 172 men chose the state of the economy as their biggest concern. Can we conclude that the proportion of women ( p1 ), choosing the state of the economy as their biggest concern, exceeds the proportion of men ( p2 )? Use a significance level of α=0.1 for the test. Step 1 of 6 : State the null and alternative hypotheses for the test. Step 2 of 6 : Find the values of the two sample proportions, pˆ1p^1 and pˆ2p^2. Round your answers to three decimal places. Step 3 of 6 : Compute the weighted estimate of p, p‾p‾. Round your answer to three decimal places. Step 4 of 6 : Compute the value of the test statistic. Round your answer to two decimal places. Step 5 of 6 : Determine the decision rule for rejecting the null hypothesis H0H0. Round the numerical portion of…The drug Ritalin is designed to stimulate the central nervous system. In a random sample of 252 boys aged ten – twelve years old, it was found that 44 of the boys were taking Ritalin. It is known that the proportion of all boys aged 13 – 15 who take Ritalin is 24%. A researcher claims that the population proportions of boys who take Ritalin aged 10 – 12 is different than boys aged 13 – 15. Can you support this claim at the 5% significance level? a. Conduct a hypothesis test to test the claim at the 5% significance level. Be sure to state you Ho and Ha, your test statistic and p-value, whether or not you reject Ho and whether you support the claim. b. Show that you can use the large sample methodology. c. Write a complete sentence describing what a Type I error is in context.