In a clinical trial of a drug intended to help people stop smoking, 126 subjects were treated with the drug for 13 weeks, and 19 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.17 as an alternative value of p, the power of the test is 0.95. Interpret this value of the power of the test.

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.7: Probability
Problem 58E: What is meant by the sample space of an experiment?
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In a clinical trial of a drug intended to help people stop smoking, 126 subjects were treated with the drug for 13 weeks, and 19 subjects experienced abdominal pain. If
someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level.
Using 0.17 as an alternative value of p, the power of the test is 0.95. Interpret this value of the power of the test.
The power of 0.95 shows that there is a % chance of rejecting the
hypothesis of p = when the true proportion is actually. That is, if the proportion of users
fp%3D
who experience abdominal pain is actually , then there is a
% chance of supporting the claim that the proportion of users who experience abdominal pain is
than
0.08.
(Type integers or decimals. Do not round.)
ce
Toc
Transcribed Image Text:In a clinical trial of a drug intended to help people stop smoking, 126 subjects were treated with the drug for 13 weeks, and 19 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.17 as an alternative value of p, the power of the test is 0.95. Interpret this value of the power of the test. The power of 0.95 shows that there is a % chance of rejecting the hypothesis of p = when the true proportion is actually. That is, if the proportion of users fp%3D who experience abdominal pain is actually , then there is a % chance of supporting the claim that the proportion of users who experience abdominal pain is than 0.08. (Type integers or decimals. Do not round.) ce Toc
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