In a hypothetical population of 2500 people, 2275 people have brown eyes and 225 people have blue eyes (the homozygous-recessive phenotype). If there are 4000 children produced by this generation, how many (i.e., what number) of the children would be expected to be heterozygous for eye color?

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Asked Nov 24, 2019
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  1. In a hypothetical population of 2500 people, 2275 people have brown eyes and 225 people have blue eyes (the homozygous-recessive phenotype). If there are 4000 children produced by this generation, how many (i.e., what number) of the children would be expected to be heterozygous for eye color?
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Expert Answer

Step 1

According to Hardy-Weinberg equilibrium, the frequency of alleles in a population can be represented by a formula p + q = 1, where p represents the frequency of the dominant allele and q represents the frequency of the recessive allele.

 

Step 2

From the given question, it is understood that,

q2225/2500
0.09
which means q is equal to 0.3
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q2225/2500 0.09 which means q is equal to 0.3

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Step 3

From the equation...

р+0.3- 1
р- 1-0.3
р 0.7
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р+0.3- 1 р- 1-0.3 р 0.7

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