In a reaction similar to Reaction 1, 3.2 g of sodium hydroxide (NaOH) is added to 100.0 g of water. A rise in temperature of 2.9 °C was noted. Assume the solution formed is water and c= 4.184 J/ (g °C).  -If the ΔH was independently calculated using Hess's Law to be -15.50kJ/mol, what is the % difference between your calculated value in C and the independently calculated value ?

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In a reaction similar to Reaction 1, 3.2 g of sodium hydroxide (NaOH) is added to 100.0 g of water. A rise in temperature of 2.9 °C was noted. Assume the solution formed is water and c= 4.184 J/ (g °C).

 -If the ΔH was independently calculated using Hess's Law to be -15.50kJ/mol, what is the % difference between your calculated value in C and the independently calculated value ?

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