2. In a reaction to make ethyl acetate, 25.5 g CH,COOH react with 11.5 gCH,OH to give a yield of 17.6 g CH COOCHs. The smaller quantity made, 17.0 g NH3, is the theoretical yield so thelimiting reactant is N,.• The percentage yield is calculated:16.1 g (actual yield)17.0 g (theoretical yield)percentage yield =x 100 = 94.7%Verify your result.The units of the answer are correct. The percentage yield is less than100%, so the final calculation is probably set up correctly.PRACTICEDetermine the limiting reactant and the percentage yield for each ofthe following.14.0 g N2 react with 3.15 g H, to give an actual yield of 14.5 g NH3.In a reaction to make ethyl acetate, 25.5 g CH3COOH react with 11.5 gCH,OH to give a yield of 17.6 g CH3COOC,H5.CH3COOH + CH;OH→ CH;COOC,H5 + H2O3 16.1 g of bromine are mixed with 8.42 g of chlorine to give an actualyield of 21.1 g of bromine monochloride.

Answered: Image /qna-images/answer/2bcdd8da-4091-402f-9227-734b97086e7b.jpg

Answered: In a reaction to make ethyl acetate,…

In a reaction to make ethyl acetate, 25.5 g CH3COOH react with 11.5 g CH5OH to give a yield of 17.6 g CH;COOC,H5. CH;COOH + C2H;OH→ CH;COOC,H5 + H2O

Chemistry for Engineering Students

3rd Edition

ISBN:9781285199023

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter4: Stoichiometry

Section: Chapter Questions

Problem 4.77PAE: The pictures below show a molecular-scale view of a chemical reaction between H2 and CO to produce...

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Concept explainers

Alkanes and Cycloalkanes

Alkanes are saturated organic compounds which are made up of C and H atoms. Alkanes have the general formula of CnH2n+2. Alkane contains sp3 hybridized carbon atoms with four sigmas (σ) bonds & every hydrogen atom is connected with one of the carbon atoms. The size of the alkane could be determined by the number of carbon atoms located in it.

Question

2. In a reaction to make ethyl acetate, 25.5 g CH,COOH react with 11.5 g CH,OH to give a yield of 17.6 g CH COOCHs.

The smaller quantity made, 17.0 g NH3, is the theoretical yield so the
limiting reactant is N,.
• The percentage yield is calculated:
16.1 g (actual yield)
17.0 g (theoretical yield)
percentage yield =
x 100 = 94.7%
Verify your result.
The units of the answer are correct. The percentage yield is less than
100%, so the final calculation is probably set up correctly.
PRACTICE
Determine the limiting reactant and the percentage yield for each of
the following.
14.0 g N2 react with 3.15 g H, to give an actual yield of 14.5 g NH3.
In a reaction to make ethyl acetate, 25.5 g CH3COOH react with 11.5 g
CH,OH to give a yield of 17.6 g CH3COOC,H5.
CH3COOH + CH;OH→ CH;COOC,H5 + H2O
3 16.1 g of bromine are mixed with 8.42 g of chlorine to give an actual
yield of 21.1 g of bromine monochloride.

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