In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6967 subjects randomly selected from an online group involved with ears. There were 1312 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho p>0.2 H p=0.2 O B. Ho p=0.2 H, p#0.2 OC. Ho p= 0.2 H p>0.2 O D. Ho p<0.2 H, p= 0.2 O E. Ho p 0.2 H p=0.2 OF. Ho p= 0.2 H, p<0.2 The test statistic is z = (Round to two decimal places as needed) The P-value is (Round to three decimal places as needed. the significance level, the null hypothesis. There is 7 evidence to support the claim that the return rate is less than 20%. Because the P-value is O of 2

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In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6967 subjects randomly selected from an online group involved with ears. There were
1312 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to
the binomial distribution.
Identify the null hypothesis and alternative hypothesis.
O A. Ho p>0.2
H p=0.2
O B. Ho p=0.2
H, p#0.2
O C. Ho p=0.2
O D. Ho p<0.2
H, p> 0.2
H, p= 0.2
O F. Ho p=0.2
O E. Ho p#0.2
H p=0.2
H, p<0.2
The test statistic is z =
(Round to two decimal places as needed.)
The P-value is
(Round to three decimal places as needed.
the significance level,
the null hypothesis. There is
7 evidence to support the claim that the return rate is less than 20%.
Because the P-value is
O of 2
Transcribed Image Text:In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6967 subjects randomly selected from an online group involved with ears. There were 1312 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho p>0.2 H p=0.2 O B. Ho p=0.2 H, p#0.2 O C. Ho p=0.2 O D. Ho p<0.2 H, p> 0.2 H, p= 0.2 O F. Ho p=0.2 O E. Ho p#0.2 H p=0.2 H, p<0.2 The test statistic is z = (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed. the significance level, the null hypothesis. There is 7 evidence to support the claim that the return rate is less than 20%. Because the P-value is O of 2
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