In a study regarding public opinion about American involvment in foreign affairs, a random sample of 40 people showed that 25 favored increasing US involvment in foreign affairs. How many more people should be included in the sample for the study to state with a 95 percent confidence that the sample proportion is within 0.04 of the population proportion? Hint: the margin of error is 0.05 where the margin of errror in confidence interval for a proportion is n = (z^2 *(p-hat)*(1-phat))/E^2); also subtract 40 from your final answer: Z = p-hat = n = n - 40 = sub tot =

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In a study regarding public opinion about American involvment in foreign affairs,
a random sample of 40 people showed that 25 favored increasing US involvment in
foreign affairs. How many more people should be included in the sample for the study
to state with a 95 percent confidence that the sample proportion is within 0.04 of the
population proportion? Hint: the margin of error is 0.05 where the margin of errror
in confidence interval for a proportion is n = (z^2 *(p-hat)*(1-phat))/E^2); also subtract 40
from your final answer:
Z =
p-hat =
n =
n - 40 =
sub tot =
Transcribed Image Text:In a study regarding public opinion about American involvment in foreign affairs, a random sample of 40 people showed that 25 favored increasing US involvment in foreign affairs. How many more people should be included in the sample for the study to state with a 95 percent confidence that the sample proportion is within 0.04 of the population proportion? Hint: the margin of error is 0.05 where the margin of errror in confidence interval for a proportion is n = (z^2 *(p-hat)*(1-phat))/E^2); also subtract 40 from your final answer: Z = p-hat = n = n - 40 = sub tot =
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