In a survey of 1398 people, 987 people said they voted in a recent presidential election. Voting records show that 68% of eligible voters actually did vote. Given that 68% of eligible voters actually did vote, (a) find the probability that among 1398 randomly selected voters, at least 987 actually did vote. (b) What do the results from part (a) suggest? (a) P(X2987)= (Round to four decimal places as needed.) (b) What does the result from part (a) suggest? OA. People are being honest because the probability of P(x2987) is less than 5%. OB. Some people are being less than honest because P(x2987) is at least 1%. OC. Some people are being less than honest because P(x ≥ 987) is less than 5%. OD. People are being honest because the probability of P(x2 987) is at least 1%.

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 50E: Flexible Work Hours In a recent survey, people were asked whether they would prefer to work flexible...
icon
Related questions
Question
K
In a survey of 1398 people, 987 people said they voted in a recent presidential election. Voting records show that 68% of eligible voters actually did vote. Given that 68% of eligible voters actually did
vote, (a) find the probability that among 1398 randomly selected voters, at least 987 actually did vote. (b) What do the results from part (a) suggest?
(a) P(X2 987)= (Round to four decimal places as needed.)
(b) What does the result from part (a) suggest?
OA. People are being honest because the probability of P(x ≥ 987) is less than 5%.
OB. Some people are being less than honest because P(x2987) is at least 1%.
OC. Some people are being less than honest because P(x ≥ 987) is less than 5%.
OD. People are being honest because the probability of P(x ≥ 987) is at least 1%.
C
Transcribed Image Text:K In a survey of 1398 people, 987 people said they voted in a recent presidential election. Voting records show that 68% of eligible voters actually did vote. Given that 68% of eligible voters actually did vote, (a) find the probability that among 1398 randomly selected voters, at least 987 actually did vote. (b) What do the results from part (a) suggest? (a) P(X2 987)= (Round to four decimal places as needed.) (b) What does the result from part (a) suggest? OA. People are being honest because the probability of P(x ≥ 987) is less than 5%. OB. Some people are being less than honest because P(x2987) is at least 1%. OC. Some people are being less than honest because P(x ≥ 987) is less than 5%. OD. People are being honest because the probability of P(x ≥ 987) is at least 1%. C
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Similar questions
Recommended textbooks for you
College Algebra
College Algebra
Algebra
ISBN:
9781337282291
Author:
Ron Larson
Publisher:
Cengage Learning
College Algebra
College Algebra
Algebra
ISBN:
9781305115545
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning
Algebra and Trigonometry (MindTap Course List)
Algebra and Trigonometry (MindTap Course List)
Algebra
ISBN:
9781305071742
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning
College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
Algebra
ISBN:
9781305652231
Author:
R. David Gustafson, Jeff Hughes
Publisher:
Cengage Learning
Holt Mcdougal Larson Pre-algebra: Student Edition…
Holt Mcdougal Larson Pre-algebra: Student Edition…
Algebra
ISBN:
9780547587776
Author:
HOLT MCDOUGAL
Publisher:
HOLT MCDOUGAL