college professor would like to estimate the proportion of students who pull an "all-nighter," meaning they study all night for an upcoming exam. She selects a random sample of 100 students from her large college and finds that the 99% confidence interval for the true proportion of students who pull an all-nighter is 0.48 to 0.62. Which of these statements is a correct interpretation of the confidence level? O Approximately 99% of all students have pulled an all-nighter. O There is a 99% probability that the true proportion of all students who pull an all-nighter is between 0.48 and 0.62. If many random samples of size 100 are selected from all students at this college, approximately 99% of the intervals would capture the true proportion who pull an all-nighter. C Approximately 99% of the sample proportions of students who pull an all-nighter, based on random samples of size 100 from the population of all students at this college, will fall between 0.48 and 0.62
college professor would like to estimate the proportion of students who pull an "all-nighter," meaning they study all night for an upcoming exam. She selects a random sample of 100 students from her large college and finds that the 99% confidence interval for the true proportion of students who pull an all-nighter is 0.48 to 0.62. Which of these statements is a correct interpretation of the confidence level? O Approximately 99% of all students have pulled an all-nighter. O There is a 99% probability that the true proportion of all students who pull an all-nighter is between 0.48 and 0.62. If many random samples of size 100 are selected from all students at this college, approximately 99% of the intervals would capture the true proportion who pull an all-nighter. C Approximately 99% of the sample proportions of students who pull an all-nighter, based on random samples of size 100 from the population of all students at this college, will fall between 0.48 and 0.62
Chapter9: Sequences, Probability And Counting Theory
Section9.7: Probability
Problem 1SE: What term is used to express the likelihood of an event occurring? Are there restrictions on its...
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Question
A college professor would like to estimate the proportion of students who pull an "all-nighter," meaning they study
all night for an upcoming exam. She selects a random sample of 100 students from her large college and finds that
the 99% confidence interval for the true proportion of students who pull an all-nighter is 0.48 to 0.62. Which of
these statements is a correct interpretation of the confidence level?
O Approximately 99% of all students have pulled an all-nighter.
O There is a 99% probability that the true proportion of all students who pull an all-nighter is between 0.48 and 0.62.
If many random samples of size 100 are selected from all students at this college, approximately 99% of the
intervals would capture the true proportion who pull an all-nighter.
C
Approximately 99% of the sample proportions of students who pull an all-nighter, based on random samples of
size 100 from the population of all students at this college, will fall between 0.48 and 0.62.
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