  In an acid-base neutralization reaction 38.74 mL of 0.500 M potassium hydroxide reacts with 50.00 mL of sulfuric acid solution. What is the concentration of the H2SO4 solution?I calculated 0.387 M , but the result marked wrong

Question

In an acid-base neutralization reaction 38.74 mL of 0.500 M potassium hydroxide reacts with 50.00 mL of sulfuric acid solution. What is the concentration of the H2SO4 solution?

I calculated 0.387 M , but the result marked wrong

Step 1

Acid-base reaction

An acid gives off its proton to a base in an acid base reaction.

Step 2

Given here, in an acid-base neutralization reaction

38.74 mL of 0.500 M potassium hydroxide reacts with 50.00 mL of sulfuric acid solution.

Reaction

2KOH(aq) + H2SO4(aq) ---> K2SO4(aq) + 2H2O(l)

So, 2 moles of KOH is neutralized with 1 mole of H2SO4

Here,

moles = molarity x volume of solution

we have,

moles ...

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