In developing an interval estimate for a population mean, a sample of 50 observations was used. The interval estimate was 19.76 ±1.32. Had the sample size been 200 instead of 50, the interval estimate would have been O A. 4.94 + 1.32 о В. 19.76 + 0.66 OC. 19.76 + 0.33 O D. 9.88 ± 1.32 In developing an interval estimate for a population mean, the interval estimate was 62.84 to 69.46. The population standard deviation was assumed to be 6.50, and a sample of 100 observations was used. The mean of the sample was O A. 13.24 о В. 6.15 о с. 56.34 O D. 62.96

In developing an interval estimate for a population mean, a sample of 50 observations was used. The interval estimate was 19.76 ±1.32. Had the sample size been 200 instead of 50, the interval estimate would have been O A. 4.94 + 1.32 о В. 19.76 + 0.66 OC. 19.76 + 0.33 O D. 9.88 ± 1.32 In developing an interval estimate for a population mean, the interval estimate was 62.84 to 69.46. The population standard deviation was assumed to be 6.50, and a sample of 100 observations was used. The mean of the sample was O A. 13.24 о В. 6.15 о с. 56.34 O D. 62.96

Name: In developing an interval estimate for a population mean, a sample of
Uploaded: 2024-03-20T07:06:16.000Z
Channel: Bartleby
Description: In developing an interval estimate for a population mean, a sample of 50 observations was used. The interval estimate was 19.76 ±1.32.Had the sample size been 200 instead of 50, the interval estimate would have beenO A. 4.94 + 1.32о В. 19.76 + 0.66O

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

If you obtained a test score of 78 on a test with an average test score of your class is 70, and SD is 4. If your class have 36 students in total, what is the 95% CI range in estimate the test score of the population [70-2.064*4, 70+2.064*4] [72-2.064*4, 72+2.064*4] [70-2.064*0.67, 70+2.064*0.67] [72-2.064*0.67, 72+2.064*0.67]
The mean ±1 sd of ln [calcium intake (mg)] among 25 females, 12 to 14 years of age, below the poverty level is 6.56 ± 0.64. Similarly, the mean ± 1 sd of ln [calcium intake (mg)] among 40 females, 12 to 14 years of age, above the poverty level is 6.80 ± 0.76. *8.7 Suppose an equal number of 12- to 14-year-old girls below and above the poverty level are recruited to studydifferences in calcium intake. How many girls should be recruited to have an 80% chance of detecting a significant difference using a two-sided test with α = .05? *8.8 Answer Problem 8.7 if a one-sided rather than a twosided test is used. *8.9 Using a two-sided test with α = .05, answer Problem 8.7, anticipating that two girls above the poverty level will be recruited for every one girl below the poverty level who is recruited.
In a recent survey of 157 WMU graduates, 117 students said that parking was too limited on campus. What is the estimate of the population proportion? What is the standard error of this estimate? Question 7 options: 1) Estimate of proportion: 0.745, Standard error: 0.0348. 2) Estimate of proportion: 0.255, Standard error: 0.0028. 3) Estimate of proportion: 0.745, Standard error: 0.0028. 4) The true population proportion is needed to calculate this. 5) Estimate of proportion: 0.255, Standard error: 0.0348.
The weights of radish seeds are normally distributed, with µ = 0.12 g and σ = 0.02 g. What is the z-score of a radish seed that weighs 0.093 g? If the contents of a seed packet weighs 30.0 g, approximately how many seeds are in it? Approximately how many seeds in the packet weigh between 0.08 g and 0.16 g.?
The research examining the effects of preschool childcare has found that children who spent time in daycare perform better on math and language tests than children who stay home with their mothers. The results show that a sample of n = 25 children who attended daycare before starting school had an average score of M = 87 with SS = 1536 on a standardized math test for which the population mean is μ = 81. The population distribution is normal. Use α= .01 a. Is this sample sufficient to conclude that the children with a history of preschool daycare are significantly better from the general population? b. Compute the 95% confidence interval. show all work
The research examining the effects of preschool childcare has found that children who spent time in day care perform better on math and language tests than children who stay home with their mothers. The results show that a sample of n = 25 children who attended day care before starting school had an average score of M = 87 with SS = 1536 on standardized math test for which the population mean is μ = 81. The population distribution is normal. Use α = .01. a. Is this sample sufficient to conclude that the children with a history of preschool day care are significantly better from the general population? b. Compute the 95% confidence interval.
State the t critical value that would be used for a 99% interval based on a sample size of 37.
For the situation described below, state the null and alternative hypotheses to be tested. (Enter != for ≠ as needed.) A new variety of pearl millet is expected to provide an increased yield over the variety presently in use, which has a mean yield of about 55 bushels per acre.
A study was done to compare the flu incidence rates at the sart and at the end of winter of a given year. A sample of 100 persons were asked for incidence of flu twice: once at the start and once at the end of winter. Sample data were as follows: a. Give 99% CI for the difference in flu incidence rates at the start and at the end of winter? b. Compute a measure of association between flue incidence at the start and at the end of winter?
a) A given distribution has a population mean, μ, of 106 and a population standard deviation, σ, of 8. What z-score would be associated with the value x = 140? b) A given distribution has a population mean, μ, of 138 and a population standard deviation, σ, of 11. What z-score would be associated with the value x = 98? c) A given distribution has a population mean, μ, of 143 and a population standard deviation, σ, of 5. Compute the raw, x-value associated with a Z-score of -2.02. d) A given distribution has a population mean, μ, of 110 and a population standard deviation, σ, of 11. Compute the raw, x-value associated with a Z-score of 1.12. e) Suppose a population is known to be normally distributed with a mean, μ, equal to 116 and a standard deviation, σ, equal to 14. Approximately what percent of the population would be between 88 and 130? f) Suppose a population is known to be normally distributed with a mean, μ, equal to 116 and a standard deviation, σ, equal to 14.…
The mean yield from process A is estimated to be 80 ± 5, where the units are percent of a theoretical maximum. The mean yield from process B is estimated to be 90 ± 3. The relative increase obtained from process B is therefore estimated to be (90 − 80)/80 = 0.125. Find the uncertainty in this estimate.
To see the effect of a relatively small error in the estimate of the amount of carbon-14 in a sample being dated, consider this hypothetical situation: a. A bone fragment found in central Illinois in the year 2000 contains 17% of its original carbon-14 content. Estimate the year the animal died. b. Repeat part (a), assuming 18% instead of 17%. c. Repeat part (a), assuming 16% instead of 17.