In each of Exercises, use the one-proportion plus-four z-interval procedure to find the required confidence interval. Interpret your results. Working with Millions. A poll by Gallup asked, “If you won 10 million dollars in the lottery, would you continue to work or stop working?” Of the 1039 American adults surveyed, 707 said that they would continue working. Obtain a 95% confidence interval for the proportion of all American adults who would continue working if they won 10 million dollars in the lottery.

Q: Out of 100 people sampled, 16 have tried marijuana. Based on this, construct a 95% confidence…

A: Obtain the 95% confidence interval for the true population proportion of people who have tried…

Q: Find the margin of error E that corresponds to the given statistics and confidence level.…

A: From the provided information, Confidence level = 98% Sample size (n) = 900 Success (p̂) = 0.40

Q: Campus athletics is interested in the proportion of registered students living on campus who play…

A: We are given that 95% confidence interval is correctly calculated from the given data as (0.12,…

Q: In a survey, the planning value for the population proportion is .25. How large a sample should be…

A: Solution: It is given that the planning value for the population proportion is 0.25. The confidence…

Q: Della has over 500 songs on her mobile phone, and she wants to estimate what proportion of the songs…

A: The formula for the confidence interval is , CI=p^± Z*p^1-p^n Where,  p^=the proportion in sample…

Q: 3. You want to find out the percent of people who use an iPhone, so you survey 120 random adults, of…

A: Here we need to construct a 95% confidence interval for the population proportion.

Q: 7. A recent study of 750 Internet users in Europe found that 35% of Internet users were women. What…

A:

Q: The County Development Agency does a survey of all the mobile home manufacturers in Clarion County…

A: X̄ = $13,550, σ = $2,000, n = 25,

Q: n a survey of 500 students, 180 students said that they prefer classes on Mondays and Wednesdays…

A:

Q: 4a) A survey asked users of Facebook, “Do you believe Facebook should be able to collect user's data…

A: a) The sample proportion is computed as follows, The value of z at 95% confidence level is 1.96,…

Q: In order to construct the 95% confidence interval, you choose which formula? O x ±1.645 × OT ±1.96 x…

A:

Q: You observe 60 customers at a coffee shop, and 82% of them tip. What is the 95% confidence interval…

A: Given : You observe 60 customers at a coffee shop, and 82% of them tip.

Q: In each of Exercises, use the two-proportions plusfour z-interval procedure to find the required…

A:

Q: Construct the 94% confidence interval estimate of the population proportion ? if the sample size is…

A:

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given Information n =87 x =48

Q: In one city, 59.6% of the 1500 students surveyed said they eat at the school cafeteria. Find the 95%…

A: Given, Sample size=n=1500 p^=0.596 α=0.05

Q: ccording to the data, calculate a 90% confidence interval for the sample mean. What was the T Score…

A: Solution: n= 30 Sample size ∑xi=642 x=∑xin=64230=21.4 Sample mean s2=∑(xi-x)2n-1=56.52414 Sample…

Q: kendall wants to estimate the percentage of vegetarians who are also vegan. She surveys 150…

A: The margin of error for the 95% confidence interval of population proportion is given as follows :…

Q: Find the confidence level and α for a. an 85% confidence interval. b. a 95% confidence interval.

A:

Q: If a student provided 90% confidence intervals in all ten questions, how many points would we expect…

A: In the given analysis, we have 10 questions and their correct answers. 10 sample responses from 10…

Q: In each of Exercises, use the one-proportion plus-four z-interval procedure to find the required…

A:

Q: The statistics department is interested in estimating the proportion of students who have majored in…

A: Here we need to find the required sample size to estimate the proportion of students who majored…

Q: A survey of 20 people asked, “If you’ve ever been married, how old were you when you were first…

A:

Q: d. Construct a 95% confidence interval estimate. How does this change your answer to part (b)?

A: Given that Sample size n = 50 Sample mean = 0.987 Population SD = 0.02 The critical value of Z at…

Q: In a survey, the planning value for the population proportion is .25. How large a sample should be…

A: We have to find sample size..

Q: In a random sample of 95 manufacturing firms, 67 indicated that their company attained ISO…

A: For part i]: Linear relationship: 1]The graph of linear relationship forms a straight line.  2] A…

Q: What Z score would be used to construct a 90% confidence level? Is it ... a. 1.65 b. 2.33 c.…

A: Confidence Level = 90 Significance Level = α = (100-90)% = 0.1 Critical value = z* = 1.65   […

Q: n our Condor Cafe, the Oxnard College Culinary Program offers the most delicious and affordable…

A: Given that, n=255,x=75

Q: In the previous example, you learned that the 95% confidence interval for the true proportion of all…

A: Calculate the point estimate and margin of error used to create this confidence interval.

Q: Find the confidence level and a for a. an 85% confidence interval.b. a 95% confidence interval.

A: The level of significance can be defined as the probability of rejecting the null hypothesis when it…

Q: Use the given confidence interval to find the margin of error and the sample mean.  (4.81, 8.09)

A: The confidence interval is given by (4.81, 8.09)

Q: In a survey conducted by CNN, 130 of the 250 people that were randomly surveyed have a savings…

A: Given data, n=250 x=130 Sample proportion p=x/n =130/250=0.52 z-value at 90% confidence is Zc=1.645

Q: Find the confidence level and a for an 88% confidence interval.

A: Here use confidence level and significance level as alternative of each other

Q: In 2017, the CDC administered the Youth Risk Behavior Survey (YRBS) to a random sample of 14,795…

A: Obtain the 99% confidence interval for the proportion of the high school students have been cyber…

Q: In a random sample of 200 people, 154 said they watched educational television. We wish to construct…

A: Given there are 200 people, 154 said they watched educational television. a) Given confidence…

Q: Use the confidence interval to find the margin of error and the sample mean.   (.364,0.500)

A:

Q: In a survey, 1000 Grade 7 students were asked if they read storybooks. There were 318 who said Yes.…

A: Givenn=1000x=318p^=3181000=0.318Confidence interval = 95%

Q: use the given degree of confidence and sample date to contruct a confidence interval for the…

A: Sample size = n = 124 Sample number of events = x = 20 Sample proportion = p̂ = x/n = (20/124) =…

Q: A soft drink company surveys 500 shoppers and finds that 61% of shoppers prefer diet soda to regular…

A:

Q: Social Networking Sites In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of…

A:

Q: a). Find a 93% confidence interval for p, the true crash risk (probability) for novice drivers, also…

A: For novice drivers, sample size n = 371, Number of crashes, X = 24 For expert drivers, sample size n…

Q: Find the confidence level and α for an 80​% confidence interval.

A: Given confidence level =80%

Q: Using your answers to parts (a) and (b), find a 95% confidence interval estimating the proportion of…

A: Here we need to construct a 95% confidence interval.

Q: (d) Use the combined data of 80 students, construct a 95% confidence interval estimate of the…

A: Given that  Total students=n=40+40=80 Number of pass students=X=28+32=60

Q: Find the confidence level and α for a. a 90% confidence interval. b. a 99% confidence interval.

A:

Q: In each of Exercises, use the one-proportion plus-four z-interval procedure to find the required…

A: In a survey, 836 out of 929online adults who are 18-29 years old said that they use social…

Q: how many samples out of 100 would you expect to not include the true population mean within their…

A: here given ,  confidence level =  90%  sample size  = 100

Q: In a​ poll, 69​% of the people polled answered yes to the question​ "Are you in favor of the death…

A: Given: Margin of errorE=0.02 Proportion of people who polled yes p^=0.69 The z value corresponding…

Q: Out of 300 people sampled, 78 had kids. Based on this, construct a 99% confidence interval for the…

A:

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.