Question
Asked Feb 8, 2020
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In each reaction box, place the best reagent and conditions from the list below.
1)
2)
3)
4)
CHяCH-CH2CI, AIClk CH3COO
NBS, ROOR, hv
ВНз/THF
CrO3, H2SO4
HЕг
Н2О2, NaOH, H20
Br2, FeBr3
CHяCH-CI, AICIS
Br2
(CH3)3CO
Pd, H2
MCPBA
Br2, H20
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In each reaction box, place the best reagent and conditions from the list below. 1) 2) 3) 4) CHяCH-CH2CI, AIClk CH3COO NBS, ROOR, hv ВНз/THF CrO3, H2SO4 HЕг Н2О2, NaOH, H20 Br2, FeBr3 CHяCH-CI, AICIS Br2 (CH3)3CO Pd, H2 MCPBA Br2, H20

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Expert Answer

Step 1

The given conversion can be done as follows :

The first step is the alkylation of benzene ring which is done through Friedel-Craft Alkylation of benzene with CH3CH2Cl, AlCl3 to form the alkylated product.

Chemistry homework question answer, step 1, image 1

Step 2

The second step is the bromination of the alkylated product with NBS, ROOR, hν to form the alkyl bromide product.

 Chemistry homework question answer, step 2, image 1

 

Chemistry homework question answer, step 2, image 2

 

 

Step 3

The third step is the elimination of reaction of alkyl bromide to form alkene with the help of strong base, (CH3)3CO-

Chemistry homework question answer, step 3, image 1

...

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