in kotlin Write two versions of a recursive palindrome check function. One version should have a block body, and the other should have an expression body. Review the lecture slide about the substring function first. Use this algorithm: if the length of the string is less than 2, return true else if the first and last characters are not equal (!=) return false else return the result of a recursive call with the substring from the second character (the one at index 1) to the second to last character. Use a main that uses a loop to test the palindrome function using this list of strings: val ss = listOf("", "A", "AA", "AB", "AAA", "ABA", "ABB", "AAAA", "AABA", "ABBA", "ABCBA", "ABCAB")

in kotlin Write two versions of a recursive palindrome check function. One version should have a block body, and the other should have an expression body. Review the lecture slide about the substring function first. Use this algorithm: if the length of the string is less than 2, return true else if the first and last characters are not equal (!=) return false else return the result of a recursive call with the substring from the second character (the one at index 1) to the second to last character. Use a main that uses a loop to test the palindrome function using this list of strings: val ss = listOf("", "A", "AA", "AB", "AAA", "ABA", "ABB", "AAAA", "AABA", "ABBA", "ABCBA", "ABCAB")

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter15: Recursion

Section: Chapter Questions

Problem 6PE

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A palindrome is a sentence that contains the same sequence of letters reading it either forwards or backwards. A classic example is '1\.ble was I, ereI saw Elba." Write a recursive function that detects whether a string is apalindrome. The basic idea is to check that the first and last letters of thestring are the same letter; if they are, then the entire string is a palindromeif everything between those letters is a palindrome.There are a couple of special cases to check for. If either the first orlast character of the string is not a letter, you can check to see if the restof the string is a palindrome with that character removed. Also, when youcompare letters, make sure that you do it in a case-insensitive way.Use your function in a program that prompts a user for a phrase andthen tells whether or not it is a palindrome. Here's another classic fortesting: '1\. man, a plan, a canal, Panama!"
For function decToBinary, write the missing parts of the recursion case. This function should return a string that stores the binary equivalent for int variable num. Example: The binary equivalent of 13 may be found by repeatedly dividing 13 by 2. So, 13 in base 2 is represented by the string "1101". Examples: decToBinary(13) -> "1101" public String decToBinary (int num) { if (num < 2) return Integer.toString(num); else return <<Missing recursive call>> + <<Missing calculation>>;}
In kotlin, Write a recursive linear search function that takes a String and a Char and returns true if the String contains the Char. The base cases are that a) the length of the String is 0 or b) the first character in the String is the character we are searching for. then Modify the linear search function so that both the String and the Char are nullable. If either is null, return false.
Write a recursive function that returns true if the digits of a positive integer are in increasing order; otherwise, the function returns false. Also, write a program to test your function.
I just need the method they are asking for Write a recursive function named checkPalindrome that takes a string as input, and returns true if the string is a palindrome and false if it is not a palindrome. A string is a palindrome if it reads the same forwards or backwards. Recall that str.charAt(a) will return the character at position a in str. str.substring(a) will return the substring of str from position a to the end of str, while str.substring(a, b) will return the substring of str starting at position a and continuing to (but not including) the character at position b. Examples: checkPalindrome("madam") -> true public boolean checkPalindrome(String s) { }
//write a recursion function that will find the largest interger in the string. Can you give me some feedback on this function public int findMax(String s,intmax) { if (s.length()== 0) return 1; for (int = 0 ; i > s.length() ;i++) if (s.charAt (i) > s.charAt(i) )) returnmax; returnmax;
Consider a network of streets laid out in a rectangular grid, In a northeast path from one point in the grid to another, one may walk only to the north (up) and to the east (right). Write a program that must use a recursive function to count the number of northeast paths from one point to another in a rectangular grid. Your program should prompt the user to input the numbers of points to the north and to east respectively, and then output the total number of paths. Notes: 1. Here is a file (timer.h download and timer.cpp download) which should be included in your program to measure time in Window or Unix (includes Mac OS and Linux) systems (use start() for the beginning of the algorithm, stop() for the ending, and show() for printing). 2. The computing times of this algorithm is very high, and the number of paths may be overflow, don't try input numbers even over 16. 3. Name your recursive function prototype as calcPath(int north, int east) to ease grading. 4. Paste your output
How to apply this python code in the problem? What are the base cases and recursive cases that should be used? def createList(n): #Base Case/s #TODO: Add conditions here for your base case/s #if <condition> : #return <value> #Recursive Case/s #TODO: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once you've completed all the TODO for this function return [] def removeMultiples(x, arr): #Base Case/s #TODO: Add conditions here for your base case/s #if <condition> : #return <value> #Recursive Case/s #TODO: Add conditions here for your recursive case/s #else: #return <operation and recursive call> #remove the line after this once you've completed all the TODO for this function return [] def Sieve_of_Eratosthenes(list): #Base Case/s if len(list) < 1 : return list #Recursive Case/s else:…
Write a recursive function PrintPattern1 to print pattern that takes two integer arguments n and k. n is the starting number while k is the ending limit.
I am working on this recursive function, and I am drawing a blank. Line 15 else if(s.charAt(0) != s.length () -1 && ............ )) Is there a String method that looks for intergers ? Suppose to look to see if it is the last value and if it is a Integer, if it is , add the vaules that intergers together for a total sum public class Finder { //Write two recursive functions, both of which will parse any length string that consists of digits and numbers. Both functions //should be in the same class and have the following signatures. //use the if/else statement , Find the base case and -1 till you get to base case //recursive function that adds up the digits in the String public static int sumIt(String s) { int sumOfNumbers =0; //if String length is less or equal to 1 retrun 1. for (int i = 0; i >= 0 ;i++) if (s.length()<= 1)//Base case = 1 return 1; //else if the CharAt(value in index at 0 = 1) is not equal to the last vaule in the string else if(s.charAt(0) != s.length ()…