In problem 49, in chapter 10 of general chemistry principles and modern applications eleventh addition, it states in the solution explanation that d is invalid because O does not complete the octet rule as it only has 2 single bonds, meaning there would be 4 electrons in its octet, however oxygen is connected to each Nitrogen through a double bond and thus has 2 double bonds which would fufill its octet. While I agree the resonance structure is invalid as the element placement in rsonance structures have to emulate that of its lewis structure, I am confused why this explanation says that oxygen does not fufill the octet when it appears to me that it does.

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter3: Chemical Bonds
Section: Chapter Questions
Problem 3.125P
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In problem 49, in chapter 10 of general chemistry principles and modern applications eleventh addition, it states in the solution explanation that d is invalid because O does not complete the octet rule as it only has 2 single bonds, meaning there would be 4 electrons in its octet, however oxygen is connected to each Nitrogen through a double bond and thus has 2 double bonds which would fufill its octet. While I agree the resonance structure is invalid as the element placement in rsonance structures have to emulate that of its lewis structure, I am confused why this explanation says that oxygen does not fufill the octet when it appears to me that it does. 

Conclusion
Reason for incorrect option:
:N
=0=N
In given structure, the number of electrons in the oxygen atom is not
satisfying its octet so it is not a valid resonance structure.
Number of electrons in octet of O = 2(number of single bond) + 4(number
of double bond) + 6 (number of triple bond) + 2(number of lone pair)
= 2 (2) +0 + 0 + 0 = 4
%|
Number of electrons in octet of N = 2(number of single bond) + 4(number
of double bond) + 6 (number of triple bond) + 2(number of lone pair)
= 0 + 4(1) + 0 + 2 (2)
= 8
Transcribed Image Text:Conclusion Reason for incorrect option: :N =0=N In given structure, the number of electrons in the oxygen atom is not satisfying its octet so it is not a valid resonance structure. Number of electrons in octet of O = 2(number of single bond) + 4(number of double bond) + 6 (number of triple bond) + 2(number of lone pair) = 2 (2) +0 + 0 + 0 = 4 %| Number of electrons in octet of N = 2(number of single bond) + 4(number of double bond) + 6 (number of triple bond) + 2(number of lone pair) = 0 + 4(1) + 0 + 2 (2) = 8
dition
Chapter 10, Problem 49E
Interpretation:
Interpret whether the following Lewis structures of dinitrogen oxide are
correct or not and determine which of them contributes more to
resonance hybrid.
Concept introduction:
Lewis dot structure is the representation which shows the bonding
between atoms present in a molecule. It shows lone pairs and bond pairs
that existing on each bonded atom.
Lewis dot structure is also known as Lewis dot formula or electron dot
structure. The bond formation between the atoms takes place due to the
sharing of valence electrons of bonded atoms while the remaining
electrons present in outer shell represented as lone pair of electrons. To
draw the Lewis structure, calculate the total number of valence electrons
in each atom and draw the structure in such a way that each atom gets its
octet configuration.
Transcribed Image Text:dition Chapter 10, Problem 49E Interpretation: Interpret whether the following Lewis structures of dinitrogen oxide are correct or not and determine which of them contributes more to resonance hybrid. Concept introduction: Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure. The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.
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