In the above circuit, the series combination of 300 ohm and 200 ohm resistor is connected to a wire at both its terminals. Thus, if a current arrives at the junction, it is always going to take the path with the least resistance. Since the wire has zero resistance ideally, no current would flow cross the highlighted 500 ohm resistor. Therefore, we can disregard this resistor in our calculation. 300 300 A 650 500 650 || 500 B Finally, the Thevenin equivalent resistance Rth is given by [(650||500) + 300]. Thevenin's equivalent voltage Vth: 2502 3002 A1 4002 5002 20V 3002 10V 2002 В B1 Since the 300 ohm resistor is open at one end, no current flows through it. Thus, the voltage at A and B is the same as A1 and B1. Voltage between A1 and B1 = (Voltage between A1 and C) + (Voltage between C and B1). The Voltage between C and B1 is 10V as it is directly connected to a 10V source. Apply mesh law in loop with i, to find voltage across 500 ohm resistor. Vso0 = 500 * i Substitute values in highlighted equation to find Vth across A and B.

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Chapter2: Electrical Quantities And Ohm’s Law
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In the above circuit, the series combination of 300 ohm and 200 ohm resistor is
connected to a wire at both its terminals. Thus, if a current arrives at the junction, it is
always going to take the path with the least resistance. Since the wire has zero
resistance ideally, no current would flow cross the highlighted 500 ohm resistor.
Therefore, we can disregard this resistor in our calculation.
300
300
A
650
500
650 || 500
B
Finally, the Thevenin equivalent resistance Rth is given by [(650||500) + 300].
Thevenin's equivalent voltage Vth:
2502
3002
A1
4002
5002
20V
3002
10V
2002
В
B1
Since the 300 ohm resistor is open at one end, no current flows through it. Thus, the
voltage at A and B is the same as A1 and B1.
Voltage between A1 and B1 = (Voltage between A1 and C) + (Voltage between C and B1).
The Voltage between C and B1 is 10V as it is directly connected to a 10V source.
Apply mesh law in loop with i, to find voltage across 500 ohm resistor.
Vso0 = 500 * i
Substitute values in highlighted equation to find Vth across A and B.
Transcribed Image Text:In the above circuit, the series combination of 300 ohm and 200 ohm resistor is connected to a wire at both its terminals. Thus, if a current arrives at the junction, it is always going to take the path with the least resistance. Since the wire has zero resistance ideally, no current would flow cross the highlighted 500 ohm resistor. Therefore, we can disregard this resistor in our calculation. 300 300 A 650 500 650 || 500 B Finally, the Thevenin equivalent resistance Rth is given by [(650||500) + 300]. Thevenin's equivalent voltage Vth: 2502 3002 A1 4002 5002 20V 3002 10V 2002 В B1 Since the 300 ohm resistor is open at one end, no current flows through it. Thus, the voltage at A and B is the same as A1 and B1. Voltage between A1 and B1 = (Voltage between A1 and C) + (Voltage between C and B1). The Voltage between C and B1 is 10V as it is directly connected to a 10V source. Apply mesh law in loop with i, to find voltage across 500 ohm resistor. Vso0 = 500 * i Substitute values in highlighted equation to find Vth across A and B.
Problem 2: Thevenin's equivalent circuit
2502
3002
4002
$5002
20V
3002
O10V
2000
B
Thevenin's equivalent resistance:
Step 1-Short circuit all the voltage sources. This means that wherever there is a
voltage source in the circuit you can replace it with a wire.
Step 2- Open circuit all the current sources meaning that wherever there is a
current source replace it with a blank (no connection).
In above circuit,
300
250
A
400
500
300
200
250 PR
300
S m - A
400 2
500
300
-B
200
Now, we can solve the resistor arrangement. Identify the series resistors and add them.
300
400 + 250 = 650
500
300 + 200 = 500
Short circuit
In the above circuit, the series combination of 300 ohm and 200 ohm resistor is
connected to a wire at both its terminals. Thus, if a current arrives at the junction, it is
always going to take the path with the least resistance. Since the wire has zero
resistance ideally, no current would flow cross the highlighted 500 ohm resistor.
Therefore, we can disregard this resistor in our calculation.
200
300
A
b50
500
650 || 500
Finally, the Thevenin equivalent resistance Rth is given by [(650||500) + 300].
Transcribed Image Text:Problem 2: Thevenin's equivalent circuit 2502 3002 4002 $5002 20V 3002 O10V 2000 B Thevenin's equivalent resistance: Step 1-Short circuit all the voltage sources. This means that wherever there is a voltage source in the circuit you can replace it with a wire. Step 2- Open circuit all the current sources meaning that wherever there is a current source replace it with a blank (no connection). In above circuit, 300 250 A 400 500 300 200 250 PR 300 S m - A 400 2 500 300 -B 200 Now, we can solve the resistor arrangement. Identify the series resistors and add them. 300 400 + 250 = 650 500 300 + 200 = 500 Short circuit In the above circuit, the series combination of 300 ohm and 200 ohm resistor is connected to a wire at both its terminals. Thus, if a current arrives at the junction, it is always going to take the path with the least resistance. Since the wire has zero resistance ideally, no current would flow cross the highlighted 500 ohm resistor. Therefore, we can disregard this resistor in our calculation. 200 300 A b50 500 650 || 500 Finally, the Thevenin equivalent resistance Rth is given by [(650||500) + 300].
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