In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal distribution to estimate the requested probabilities.Do you try to pad an insurance claim to cover your deductible? About 41% of all U.S. adults will try to pad their insurance claims! Suppose that you are the director of an insurance adjustment office. Your office has just received 132 insurance claims to be processed in the next few days. Find the following probabilities. (Round your answers to four decimal places.)(a) half or more of the claims have been padded (b) fewer than 45 of the claims have been padded (c) from 40 to 64 of the claims have been padded (d) more than 80 of the claims have not been padded

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Asked Dec 11, 2019
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In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal distribution to estimate the requested probabilities.

Do you try to pad an insurance claim to cover your deductible? About 41% of all U.S. adults will try to pad their insurance claims! Suppose that you are the director of an insurance adjustment office. Your office has just received 132 insurance claims to be processed in the next few days. Find the following probabilities. (Round your answers to four decimal places.)

(a) half or more of the claims have been padded
 

(b) fewer than 45 of the claims have been padded
 

(c) from 40 to 64 of the claims have been padded
 

(d) more than 80 of the claims have not been padded
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Step 2

It is given that sample size n is 132 and p is 0.41.

If np ≥ 5 and n(1–p) ≥ 5 then it is appropriate to use the normal approximation to the binomial.

In this case,

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пр3 (132)(0.41) = 54.12 >5 п(1-р) -132(1- 0.41) = 77.88 >5

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Step 3

Hence, it is appropriate to use the normal approximation to the binomial.

a)

The probability of half or...

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P(x266)= P(x >66– 0.5) (Using continuity correction) = P(x > 55.5) %3D 55.5– 54.12 х — пр mp(1- p) = P(z>0.24) 5.6507 %3D =1-P(:<0.24) (Using standard normal table) =1-0.5948 = 0.4052

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Advanced Topics in Statistics

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